1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ozzi
3 years ago
14

Based on the mole ratios, what can most likely be predicted?

Chemistry
1 answer:
omeli [17]3 years ago
3 0
From mole ratios, the mass ratio of different elements can be predicted. Also the volume can be predicted based on density for liquids and ideal gas law equation for gases. From the mole ratios, the empirical formula can be predicted, as well as the molecular formula given another data which is mass of the sample.
You might be interested in
What happens when your face is near the spoon. Please specify.​
aleksandrvk [35]

Answer:

RBCs are disc-shaped with a flatter, concave center. This biconcave shape allows the cells to flow smoothly through the narrowest blood vessels. ... Many RBCs are wider than capillaries, but their shape provides the needed flexibility to squeeze through

8 0
2 years ago
Given the ion C2O4-2, what species would you expect to form with each of the following ions?
Ksivusya [100]

Answer:

A. K₂C₂O₄          Potassium oxalate

B. CuC₂O₄          Copper oxalate

C. Bi₂(C₂O₄)₃         Bismuth (III) oxalate

D. Pb(C₂O₄)₂         Lead (IV) oxalate

E. (NH₄)₂C₂O₄       Ammonium oxalate

F. HC₂O₄⁻             Acid oxalate

Explanation:

C₂O₄⁻²  → oxalate anion

This is the conjugate base from the H₂C₂O₄ which is the oxalic acid. A weak dyprotic acid that can release 2 protons.

A. 2K⁺  +  C₂O₄⁻²  → K₂C₂O₄          Potassium oxalate

It can be formed by the neutralization of the acid with the base

H₂C₂O₄  + 2KOH  → K₂C₂O₄  +  2H₂O

B. Cu²⁺ +  C₂O₄⁻²   ⇄  CuC₂O₄  ↓

This is a precipitate.

C.  2Bi³⁺  +  3C₂O₄⁻²   ⇄  Bi₂(C₂O₄)₃  ↓

This is a precipitate.

D.  Pb⁴⁺ +  2C₂O₄⁻²   ⇄  Pb(C₂O₄)₂  ↓

This is a precipitate.

E. 2NH₄⁺  +  C₂O₄⁻²   ⇄  (NH₄)₂C₂O₄  ↓

This is a precipitate.

F. This is the conjugate strong base, for the weak acid

H⁺  +  C₂O₄⁻²   ⇄  HC₂O₄⁻

HC₂O₄⁻  + H₂O  ⇄  C₂O₄⁻²  +  H₃O⁺    Ka

HC₂O₄⁻  + H₂O  ⇄  H₂C₂O₄  +  OH⁻    Kb

HC₂O₄⁻  is an amphoteric compound

6 0
3 years ago
Explain the role of a primary consumer and a secondary consumer in a food web.
Usimov [2.4K]

Answer:

Explanation:

Secondary consumers are organisms that eat primary consumers for energy. Primary consumers are always herbivores, or organisms that only eat autotrophic plants.

Carnivores only eat other animals, and omnivores eat both plant and animal matter.

7 0
3 years ago
What's lithium scientific name?
disa [49]
Well it's an alkali metal if that's what you're asking<span />
7 0
3 years ago
Are atoms the smallest particles we know about, or are there smaller ones?
Schach [20]

Answer:

That we know about yes, but physicians still say there are more things out there. (we do not know about these yet tho)

Explanation:

7 0
3 years ago
Other questions:
  • Why does Hg2+ have a negative standard entropy
    6·1 answer
  • The increase in the population of people living in urban areas will cause a decrease in urban sprawl.
    15·2 answers
  • If a temperature increase from 12.0 ∘C to 21.0 ∘C doubles the rate constant for a reaction, what is the value of the activation
    5·1 answer
  • What is the diagram of 2CO2
    12·1 answer
  • Purpose of tanning in the leather industry is to
    9·1 answer
  • A compound of Calcium is used for disinfecting drinking water. Identify the compound.
    5·1 answer
  • A teacher is demonstrating physical and chemical changes to her class. Which action should they use to demonstrate a chemical ch
    6·1 answer
  • Imagine the following scenario involving marbles as "radioactive isotopes".
    12·1 answer
  • How many GRAMS are in 3.78 mol of NaOH?<br><br> A. 150 g/mol<br> B. 151.12 g/mol<br> C. 151.1 g/mol
    10·1 answer
  • HELPPPPPPPP ILLL APPLEPAY YOU 20 dollars
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!