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otez555 [7]
2 years ago
15

Consider the unbalanced equation for the oxidation of butene. C4H8 + 6O2 Right arrow. CO2 + H2O For each molecule of C4H8 that r

eacts, how many molecules of carbon dioxide and water are produced?
Chemistry
1 answer:
Law Incorporation [45]2 years ago
8 0

Answer:

4 molecules of carbon dioxide (CO₂) and 4 molecules of water (H₂O)

Explanation:

The unbalanced chemical equation is:

C₄H₈ + 6 O₂ →  CO₂ +  H₂O

To balance the equation, we have to write a coefficient of 4 for CO₂ and a coefficient of 4 for H₂O, as follows:

C₄H₈ + 6 O₂ → 4 CO₂ + 4 H₂O

Now, we can see that 4 molecules of carbon dioxide (CO₂) and 4 molecules of water (H₂O) are produced for each molecule of C₄H₈.

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The substances sodium (Na), oxygen (O2), and sodium oxide (Na20) participate in this chemical reaction
Margaret [11]

Answer:

C

Explanation:

This is a synthesis or a combination reaction , which involves the oxygen combining with sodium to make one compound.

hope it helps.

you're welcome.

8 0
3 years ago
B. Which of the following compounds can
Tamiku [17]

Answer:

The correct answer is:

d. Na2S, NaF

4 0
3 years ago
Read 2 more answers
An astronomer observes an asteroid in the solar system. He notes that the asteroid is three times farther from the Sun than Eart
ozzi

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

7 0
3 years ago
What is the minimum of acetic anhydride (102.1 g/mol) required to react completely with the 2.94 grams of salicylic acid? What v
Lady bird [3.3K]

Answer:

a) the minimun of acetic anhydride required for the  reaction is 2.175 g (CH3CO)2O

b) V acetic anhydride = 2.010 mL

Explanation:

  • balanced reaction:

      C6H4OHCOOH + (CH3CO)2O  ↔  C9H8O4 + C2H4O2

⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH

⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O /  mol  C6H4OHCOOH ) = 0.0213 mol (CHECO)2O

⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O

b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O

4 0
2 years ago
PLS HELP THE QUESTION IS ON THE PICTURE
IceJOKER [234]

<u>Concepts used:</u>

1 mole of an element or a compound has 6.022 * 10²³ formula units

So, we can say that: <em>Number of formula units = number of moles * 6.022*10²³</em>

number of moles of an element or a compound = given mass/molar mass

<u>__________________________________________________________</u>

<u>003 - </u><u>Number of CaH₂ formula units in 6.065 grams</u>

Number of Moles:

We know that the molar mass of CaH₂ is 42 grams/mol

Number of Moles of CaH₂ = given mass/molar mass

Number of moles = 6.065 / 42

Number of moles = 0.143 moles

Number of Formula units:

Number of formula units = number of moles * 6.022*10²³

= 0.143 * 6.022 * 10²³

= 0.86 * 10²³ formula units

__________________________________________________________

<u>004 </u><u>- Mass of 6.34 * 10²⁴ formula units of NaBF₄</u>

Number of Moles:

We mentioned this formula before:

<em>Number of formula units = number of moles * 6.022*10²³</em>

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variable

Number of moles = 6.34 * 10²⁴ / 6.022*10²³

Number of moles=  10.5 moles

Mass of 10.5 moles of NaBF₄:

Molar mass of NaBF₄ = 38 grams/mol

Mass of 10.5 moles = 10.5 * molar mass

Mass of 10.5 moles = 10.5 * 38

Mass = 399 grams

__________________________________________________________

<u>005</u><u> - Number of moles in 9.78 * 10²¹ formula units of CeI₃</u>

Number of Moles:

We have the formula:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles   OR   0.016 moles

3 0
2 years ago
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