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romanna [79]
3 years ago
6

What mass of hydrogen gas would be produced if 46g of sodium was reacted with water?

Chemistry
1 answer:
bezimeni [28]3 years ago
4 0

Answer: 2g of H2 will be produced

Explanation:Please see attachment for explanation

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A piece of brass is found to have a mass of 24.32 g. When placed in a graduated cyclinder with an initial reading of 5.60 mL the
Jobisdone [24]

Answer:

\rho=3.1g/mL

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

\rho =\frac{m}{V}

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

V=13.50mL-5.60mL=7.9mL

The density of the piece of brass turns out:

\rho =\frac{24.32g}{7.9mL}\\\\\rho=3.1g/mL

Best regards.

4 0
3 years ago
Is sodium laureth sulfate ionic or covalent?
stepladder [879]

Answer: Covalent

Explanation:

7 0
3 years ago
The freezing point of diet soda is higher than the freezing point of regular soda, but lower than 0 degrees celcius, the freezin
Zepler [3.9K]

Answer:

Explanation:

Both Diet Soda and regular soda contain sweeteners.

When a solute is dissolved in solution, the solution undergoes *freezing point depression* it freezing point reduces. The magnitude of freezing point depression is directly proportional to the amount of solute in a solution.

Since soda Both regular or diet soda contains more solute than water , their freezing point is will consequently be lower than water

4 0
3 years ago
Complete the chart. (Remember to enter a "0" if necessary.)
antoniya [11.8K]
Just remember how many electrons can each sublevel hold.

S=2
P=6
D=10

Since we have 10 for atomic number, we can assume we have 10 electrons

1S2
2S2
2P6
The rest have zero because we already have 10 (2+2+6=10)
3 0
3 years ago
Read 2 more answers
A plot of binding energy per nucleon Eb A versus the mass number (A) shows that nuclei with a small mass number have a small bin
Illusion [34]

Answer:

6He =   4.90 MeV/Nucleon

8Li =     5.18  MeV / Nucleon

62Ni =   8.82 MeV / Nucleon

115 In =  8.54 MeV / Nucleon

Explanation:

Our strategy here is to remember that when the mass of a given nuclei is calculated from the sum of the mass of its  protons and neutrons, this mass is greater than  the actual  value . This is the mass defect.

Now this mass defect we can convert to energy  by utilizing Einstein´s equation, E = mc².This is  the binding energy.

For 6He with actual mass 6.0189 u ( He has Z = 2, that is 2 protons )

mass protons =   2 x 1.0078 u  =  2.0516 u

mass neutrons = 4 x 1.0087 u  =  4.0348 u

predicted mass = (2.0516 + 4.0348) u = 6.0504 u

mass defect = (6.0504 - 6.0189) u = 0.0315 u

Now we need to convert this mass expressed in atomic mass units to kilograms ( 1 u = 1.66054 x 10⁻²⁷ Kg )

0.0315 u x 1.66054 x 10⁻²⁷ Kg =5.231 x 10⁻²⁹ Kg

E =5.231x 10⁻²⁸ Kg x (3 x 10⁸ m/s )² = 4.707 x 10⁻¹²J

Finally we will convert this energy in Joules to eV

E = 4.707 x 10⁻¹²  J x 6.242 x 10¹⁸ eV/J = 2.94 x 10⁷ eV = 29.4 MeV

E per nucleon for 6He = 29.4 MeV / 6 =4.90 MeV / Nucleon

Now the calculations for the rest of the nuclei are performed in similar manner with the following results:

8Li = 5.18 MeV / Nucleon

62Ni = 8.82 MeV / Nucleon

115 In =  8.54 MeV / Nucleon

8 0
3 years ago
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