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Reil [10]
3 years ago
14

A toy car is moving along with 0.40 joules of kinetic energy if it’s speed is double then it’s new kinetic energy will be ?

Physics
1 answer:
ddd [48]3 years ago
3 0

Answer: .8

Explanation: because .40×2 =.8

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What radiation do remote controls use?
dalvyx [7]

Answer:

infra red radiation is used

3 0
3 years ago
An object accelerates from rest and travels 53 m west in 5.2 s. Determine the acceleration
zmey [24]

Answer:

20.4m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Distance  = 53m

Time  = 5.2s

Unknown:

Acceleration  = ?

Solution:

This is a linear motion and we use the right motion equation;

        S = ut  + \frac{1}{2}at²

S is the distance

u is the initial velocity

a is the acceleration

t is the time

 Insert the parameters and solve;

       53  = (0x 5.2) +  \frac{1}{2} x a x 5.2

       53  = 2.6a

         a = \frac{53}{2.6}  = 20.4m/s²

6 0
3 years ago
What roles does society,politics and economics play In science ?
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I believe the website www.asanet.org will help (:
7 0
3 years ago
Helllppp mee!
Fed [463]

Given:

m = 0.14 kg

v = 18 m/s

To find:

Kinetic energy= ?

Explanation:

Kinetic energy of the object is possessed when the object is in motion. It is define as the work done required to accelerate a body from rest to motion. Unit of energy is Joule and it is same as unit of work done. Energy is nothing but the capacity to do work.

Solution:

Kinetic energy of the ball is given by,

Kinetic energy = \frac{1}{2}m v^{2}

m = 0.14 kg

v = 18 m/s

Kinetic energy = \frac{1}{2}(0.14) (18)^{2}

Kinetic energy = 226.8 Joule

5 0
3 years ago
Read 2 more answers
Two loudspeakers emit identical sound waves along the x-axis. The sound at a point on the axis has maximum intensity when the sp
EleoNora [17]

The concept required to solve this problem is related to the wavelength.

The wavelength can be defined as the distance between two positive crests of a wave.

The waves are in phase, then the first distance is

\Delta x_1 = 20cm

And out of the phase when

\Delta x_2 = 30cm

Thus the wavelength is

\Delta x_2-\Delta x_1 = \frac{\lambda}{2}

Here,

\lambda =  Wavelength

If we rearrange the equation to find it, we will have

\lambda = 2 (\Delta x_2-\Delta x_1 )

\lambda= 2(30-20)

\lambda = 20cm

Therefore the wavelength of the sound is 20cm.

5 0
4 years ago
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