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Darya [45]
2 years ago
14

Your car is initially at rest when you hit that gas and the car begins to accelerate. The forward force of the car is 5630 N whi

le the resisting force total 330 N. The car has a mass of 1313 kg and the acceleration lasts for 2.6s. What is the final speed of the car and how much ground does it cover during this acceleration?
Physics
1 answer:
Neporo4naja [7]2 years ago
6 0
330...................
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Let the first car's average speed be x

The second car's speed would be x+5

2(x+(x+5))=210

2x+5=105

2x=100

x=50

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3 years ago
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The average intensity of light emerging from a polarizing sheet is 0.708 W/m2, and that of the horizontally polarized light inci
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Answer:

Angle θ = 30.82°

Explanation:

From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ

where;

I_o is the intensity of the polarized wave before passing through the filter.

In this question,

I is 0.708 W/m²

While I_o is 0.960 W/m²

Thus, plugging in these values into the equation, we have;

0.708 W/m² = 0.960 W/m² •cos²θ

Thus, cos²θ = 0.708 W/m²/0.960 W/m²

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Explanation:

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A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
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Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

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Distance x = 0.097 m

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Using stored energy in spring

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Using gravitational potential energy

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E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

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Answer:

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