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Darya [45]
3 years ago
14

Your car is initially at rest when you hit that gas and the car begins to accelerate. The forward force of the car is 5630 N whi

le the resisting force total 330 N. The car has a mass of 1313 kg and the acceleration lasts for 2.6s. What is the final speed of the car and how much ground does it cover during this acceleration?
Physics
1 answer:
Neporo4naja [7]3 years ago
6 0
330...................
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Answer:

48 m

Explanation:

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First convert km/h to m/s

(97 × 1000)/3600

97000/3600

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As the train is decelerating, final velocity V = 0 and acceleration a will be negative. Using third equation of motion

V^2 = U^2 - 2as

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The westbound train

Convert km/h to m/s

(127×1000)/3600

127000/3600

35.2778 m/s

Using third equation of motion

V^2 = U^2 - 2as

0 = 35.2778^2 - 2 × 4.2 × S

1244.52 = 8.4S

S = 1244.52/8.4

S2 = 148.2 m

S1 + S2 = 103.7 + 148.2 = 251.86

The distance between them once they stop will be

300 - 251.86 = 48.14 m

Therefore, the distance between them once they stop is 48 metres approximately.

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3 years ago
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How many valence electrons does boron have
mel-nik [20]
The correct answer is 2
6 0
4 years ago
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710 mm= ______________cm<br>​
love history [14]

Answer:

71 cm

Explanation:

Every 100 mm is equal to 10 cm. Hope this helps!

4 0
3 years ago
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3. Two cars, both with a mass of 500 kg, are traveling down a road. The first car has a velocity of 65 m/s east and the second c
fenix001 [56]

Answers:

a) Momentum for Car 1: p_{1}=32500kg.m/s East

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Explanation:

a) The linear momentum p is given by the following equation:

p=m.v (1)

Where m is the mass of the object and v its velocity.

In this case both cars have a mass of 500kg but different velocities (v_{1}=65m/s east for car 1 and v_{2}=85m/s west for car 2).

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p_{1}=32500kg.m/s (4)

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p_{2}=m.v_{2} (5)

p_{2}=(500kg)(85m/s) (6)

p_{2}=42500kg.m/s (7)

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