Answer:
the comparison of known quantity to unknown quantity or standard guantity is called measurment
Answer:
Explanation:
His Kinetic energy = 1/2 m v^2
v = 5 m/s
m = 75 kg
Ke = 1/2 75 * 5^2
Ke = 937.5 Joules
This will be converted to PE when he reaches the maximum height he reaches. In other words KE = PE
PE = m * g * h
m = 75
g = 9.81
h = ?
PE = 937.5
937.5 = 75 * 9.81 * h
937.5 = 735.75 * h
937.5/735.75 = h
h= 1.27 meters
Answer:
Given that
V2/V1= 0.25
And we know that in adiabatic process
TV^န-1= constant
So
T1/T2=( V1 /V2)^ န-1
So = ( 1/0.25)^ 0.66= 2.5
Also PV^န= constant
So P1/P2= (V2/V1)^န
= (1/0.25)^1.66 = 9.98
A. RMS speed is
Vrms= √ 3RT/M
But this is also
Vrms 2/Vrms1= (√T2/T1)
Vrms2=√2.5= 1.6vrms1
B.
Lambda=V/4π√2πr²N
So
Lambda 2/lambda 1= V2/V1 = 0.25
So the mean free path can be inferred to be 0.25 times the first mean free path
C. Using
Eth= 3/2KT
So Eth2/Eth1= T2/T1
So
Eth2= 2.5Eth1
D.
Using CV= 3/2R
Cvf= Cvi
So molar specific heat constant does not change
Answer:
The average velocity during the sprint is 5.43 m/s.
Explanation:
Given that,
Distance = 50 m
Time = 9.2 sec
Total time = 54 sec
We need to calculate the average velocity during the sprint
Using formula of average velocity
Where, D = total displacement
T = total time
Put the value into the formula
Hence, The average velocity during the sprint is 5.43 m/s.