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3 years ago

6 1/3 - 4 1/9 I need help again

Mathematics

2 answers:

vitfil [10]3 years ago

7 0

Answer:

2.222

Step-by-step explanation:

Hope this helps :)

Pls make brainliest :3

And have an amazing day <3

wolverine [178]3 years ago

3 0

Answer:

2 2/9

Step-by-step explanation:

so if we want to be able to substract, we're gonna multiply the 1/3 times three so the result come out to 3/9 and now we are able to substract, so 6 3/9 - 4 1/9 is equal to 2 2/9

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Answer:

$V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3$

$V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36$

Step-by-step explanation:

For this case we have the following plot on the figure attached.

We know on this case that $x = -2y+6$ represent our radius for the square, since we need cross sections perpendicular to the y axis.

We find the intersection points like this:

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Since we are assuming squares for the cross sections the area is given by $A = r^2$ where r = x= -2y+6.

Since our radius is on terms of x we can create a integral with limits on x in order to find the volume, And we can use the following integral in order to find the volume.

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On the left part we are using the following property from algebra:

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$(-2y+6)^2 = (-2y)^2 +2*(-2y)(6) +(6)^2 = 4y^2 -24y+36$

And after do the integral we got this:

$V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3$

$V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36$

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