Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
The equation that models the difference in the projected enrollments for
public schools and private schools as a function of the number of years
since 1985 is B - R = (-18.53t^2 + 975.8t + 48140) - (80.8t + 8049) = -18.53t^2 + 975.8t + 48140 - 80.8t - 8049 = -18.53t^2 + 895t + 40091
1.-28×-28×-28+13×13×13+16×16×16
=21,952+2,197+4,096
=28,245.
2.12×12×12+-7×-7×-7+-5×-5×-5
=1,728+-343+-125
=1,260
<span>3/7 - 10/7
= - 7/7
= -1
answer
-1</span>
Answer:
The question has some details missing; i.e
a. What is the probability that the shopper has neither type of card?
b. What is the probability that the shopper has both types of card?
c. What is the probability the individual has a Visa card but not a Mastercard? (Hint: You will use the answer)
a) 0.24
b) 0.24
c) 0.36
Step-by-step explanation:
The detailed steps is shown in the attachment.
