Given: Mass of Mars Mm = 6.24 x 10²³ Kg;
Mass of Phobos Mp = 9.2 x 10¹⁵ Kg
Gravitational Force F = 4.47 X 10¹⁵ N
Gravitational constant G = 6.67 X 10⁻¹¹ N m²/Kg²
Radius r = ?
Formula: F = GMmMp/r² derive r
r = √GMmMp/F
r = √(6.67 x 10⁻¹¹ N m²/Kg²)(6.24 x 10²³ Kg)(9.2 x 10¹⁵ Kg)/4.47 x 10¹⁵ N
r = √(6.67 x 10⁻¹¹ N m²/Kg²)5.74 x 10³⁹ Kg²/4.47 x 10¹⁵ N
r = √8.57 x 10¹³ m
r = 9,257,429 m
or r = 9.26 x 10⁶ m
Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.
By definition, the impulse is
Answer: 78 N-s
Answer: If the balloon acquires charge, Sam's hair loses charge.
Explanation:
I JUST GOT THIS QUESTION RIGHT ON THE IA4 <3
Answer:
Explanation:
Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 ) friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .
Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A
friction force = .4 x 2.5 x 9.8
= 9.8 N
net force on block A = P - 9.8
acceleration = ( P - 9.8 ) / 2.5
force on block B = 9.8
acceleration = force / mass
= 9.8 / 6
for common acceleration
( P - 9.8 ) / 2.5 = 9.8 / 6
( P - 9.8 ) / 2.5 = 1.63333
P = 13.88 N .
The correct answer would be A) the lenses of the eye change the size of images
