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Dafna11 [192]
4 years ago
12

Which human body system provides nutrients for the body by breaking down food? *

Physics
1 answer:
dimaraw [331]4 years ago
6 0

Answer:

The digestive system provides nutrients to the body by breaking down food.

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The rate at which work is done is ......,.....​
Lana71 [14]

Answer:

Power

Explanation:

Power is the rate at which work is done

8 0
3 years ago
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A simple machine where an inclined plane is wrapped in a spiral is called a centripetal ramp.
tamaranim1 [39]

Answer: False

Explanation:

5 0
3 years ago
Why did John Dalton describe atoms as solid spheres, and did he think all spheres were the same?
Ray Of Light [21]
Go here to get some help now a=can you help me i posted it on your profile


 https://www.khanacademy.org/science/chemistry/electronic-structure-of-atoms/history-of-atomic-struct...
8 0
4 years ago
The gas sample has a volume of 45.1 μL at 24.7 °C. What is the volume of the gas after the sample is heated to 37.2 °C at consta
likoan [24]

Answer:

   V₂  = 46.99 μL.

Explanation:

Given that

V₁ = 45.1 μL

T₁ = 24.7°C  = 273 + 24.7 = 297.7 K

T₂ = 37.2°C = 273+37.2=310.2 K

Lets take  ,The final volume = V₂  

We know that ,the ideal gas equation  

If the pressure of the gas is constant ,then we can say that

\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}

{V_2}=V_1\times \dfrac{T_2}{T_1}

Now by putting the values in the above equation we get

{V_2}=45.1\times \dfrac{310.2}{297.7}\ \mu \ L

V₂  = 46.99 μL.

The final volume will be 46.99 μL.

7 0
3 years ago
Calculate the approximate force on a square meter (1.00 m3) of sail, given the horizontal velocity of the wind is 6.00 m/s paral
KiRa [710]

Answer:

The force exerted on square meter of cubic sail is F = 15.3 N  

Explanation:

Given:-

- The face area of cubic sail, A = 1 m^2

- The velocity at frontal face, v1 = 6.0 m/s

- The velocity at back face, v2 = 3.5 m/s

- The density of air. ρ = 1.29 kg/m^3

Find:-

Calculate the approximate force on a square meter (1.00 m3) of sail

Solution:-

- We will apply the Bernoulli's equation to the flow of air around the cubic sail. Assuming that elevation changes are negligible. The constant elevation Bernoulli's equation is:

                           P1 + ρ*v1^2 / 2 = P2 + ρ*v2^2 / 2  

- The force (F) applied by any fluid is given by:

                           F = ( P2 - P1 )*A

- Re-arranging bernoulli's expression:

                          P2 - P1 = ρ/ 2 [ v2^2 - v1^2 ]

- Multiple the equation by area A:

                          A*[P2 - P1] = A*ρ/ 2 [ v1^2 - v2^2 ]

                          F = A*ρ/ 2 [ v1^2 - v2^2 ]

- Plug in the values:

                         F = (1)*(1.29/2)*[ 6^2 - 3.5^2 ]

                         F = 15.3 N  

7 0
4 years ago
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