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RideAnS [48]
3 years ago
8

What happens when a light ray is parallel to the principal axis ?

Physics
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

Any incident ray traveling parallel to the principal axis of a converging lens will refract through the lens and travel through the focal point on the opposite side of the lens. ... These rays of light will refract when they enter the lens and refract when they leave the lens.

Hope this helps...

You might be interested in
How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800
ozzi

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2

The inductance of the solenoid is given by;

L = \frac{\mu_0 N^2A}{l} \\\\L =  \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

8 0
3 years ago
What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?
Vlad1618 [11]

Answer:

<h3>The answer is 36,400 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 1,300 kg

speed / velocity = 28 m/s

We have

momentum = 1,300 × 28

We have the final answer as

<h3>36,400 kgm/s</h3>

Hope this helps you

7 0
3 years ago
What is the difference between a spring and a stream?
Lena [83]
<span>A spring is water coming from under the ground to the surface of the earth and a stream is water that is running along the ground through a trench like place on earth down a hill or steep a area.</span>
3 0
3 years ago
A rock is thrown directly upward from the edge of a flat roof of a building that is 56.3 meters tall. The rock misses the buildi
Vlada [557]

Explanation:

Given that,

Distance, d = -56.3 m

It strikes the ground 4.00 seconds after being thrown.

Using second equation of motion to find the speed was the rock thrown. So,

d=ut+\dfrac{1}{2}at^2

Here, a = -g

d=ut-\dfrac{1}{2}gt^2\\\\-56.3=u(4)-4.9(4)^2\\\\-56.3=4u-78.4\\\\u=5.52\ m/s

Let it will cover a distance of s meters. So,

s=\dfrac{v^2-u^2}{-2g}\\\\s=\dfrac{0^2-(5.52)^2}{-2\times 9.8}\\\\s=1.55\ m

4 0
3 years ago
Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into th
ch4aika [34]

Answer:

<em>The third piece moves at 6.36 m/s at an angle of 65° below the horizon</em>

Explanation:

Linear Momentum

It's a physical magnitude that measures the product of the velocity by the mass of a moving object. In a system where no external forces are acting, the total momentum remains unchanged regardless of the interactions between the objects in the system.

If the velocity of an object of mass m is \vec v, the linear momentum is computed by

\displaystyle \vec{P}=m.\vec{v}

a)

The momentum of the board before the explosion is

\displaystyle \vec{P}_{t1}=m_t\ \vec{v}_o

Since the board was initially at rest

\displaystyle \vec{P}_{t1}=

After the explosion, 3 pieces are propelled in different directions and velocities, and the total momentum is

\displaystyle \vec{P}_{t2}=m_1\ \vec{v}_1\ +\ m_2\ \vec{v}_2+m_3\ \vec{v}_3

The first piece of 2 kg moves at 10 m/s in a 60° direction

\displaystyle \vec{v}_1=(10\ m/s,60^o)

We find the components of that velocity

\displaystyle \vec{v}_1=

\displaystyle \vec{v}_1=m/s

The second piece of 1.2 kg goes at 15 m/s in a 180° direction

\displaystyle \vec{v}_2=(15,180^o)

Its components are computed

\displaystyle \vec{v}_2=(15\ cos180^o,15\ sin180^o)

\displaystyle \vec{v}_2=(-15,0)\ m/s

The total momentum becomes

\displaystyle P_{t2}=2+1.2+m_3\ \vec{v}_3

Operating

\displaystyle P_{t2}=++m_3\ \vec{v}_3

Knowing the total momentum equals the initial momentum

\displaystyle P_{t2}=+m_3\ \vec{v}_3=0

Rearranging

\displaystyle m_3\ \vec{v}_3=

Calculating

\displaystyle m_3\ \vec{v}_3=

This is the momentum of the third piece

b)

From the above equation, we solve for \vec v_3:

\displaystyle \vec{v}_3=\frac{1}{3}

\displaystyle \vec{v}_3=m/s

The magnitude of the velocity is

\displaystyle \vec{v}_3|=\sqrt{2.67^2+(-5.77)^2}=6.36

And the angle is

\displaystyle tan\theta =\frac{-5.77}{2.67}=-2.161

\displaystyle \theta =-65.17^o

The third piece moves at 6.36 m/s at an angle of 65° below the horizon

5 0
3 years ago
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