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lorasvet [3.4K]
3 years ago
15

Disconnecting a circuit while in operation can create a voltage blank

Engineering
1 answer:
zlopas [31]3 years ago
5 0

Answer:

what is the question

Explanation:

confused

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Compute the volume percent of graphite, VGr, in a 3.1 wt% C cast iron, assuming that all the carbon exists as the graphite phase
Arte-miy333 [17]

Answer:

The volume percent of graphite is 9.9%

Explanation:

Given;

weight percent of graphite, C = 3.1wt%

density of ferrite, \rho _f = 7.9 g/cm³

density of graphite, \rho _g = 2.3 g/cm³

Determine the mass fraction;

W_f = \frac{C_g - C_0}{C_g -C_f} \\\\W_f =\frac{100 - 3.1}{100-0}\\\\W_f = 0.969\\\\\\W_g = \frac{C_0 - C_a}{C_g -C_f} \\\\W_g =\frac{3.1-0}{100-0}\\\\W_g = 0.031

Determine the volume fraction;

V = \frac{W_g/ \rho_g}{W_f / \rho_f \ + \ W_g / \rho_g} *100 \%\\\\V = \frac{0.031/ 2.3}{0.969 / 7.9 \ + 0.031 / 2.3}*100\%\\\\V = 9.9\%

Therefore, the volume percent of graphite is 9.9%

8 0
3 years ago
A mass of 5 kg of saturated liquid-vapor mixture of water is contained in a piston-cylinder device at 125 kPa. Initially, 2 kg o
Likurg_2 [28]

Answer:

See attached pictures.

Explanation:

See attached pictures for detailed explanation.

8 0
4 years ago
Storing parts outside doesn't cause any environmental risks as long as the items are covered.
telo118 [61]

Answer:

False

Explanation:

3 0
3 years ago
Read 2 more answers
What is the advantage of having the engine in the front of the car?
Ugo [173]

Answer:

<h2>No advantages bro!!</h2>

Explanation:

hehehehe DONTTTT report my answer

8 0
3 years ago
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What is the air change rate (ACH) for a 100 ft^2 (9.3 m^2) space with a 10 ft (3.0 m) ceiling and an airflow rate of 200 cfm (95
kakasveta [241]

Answer:

The ACH is 12/h

Solution:

As per the question:

Area of the space, A_{s} = 100 ft^{2}

Height of the given space, h = 10 ft

Air flow rate, Q_{a} = 200 cfm

Now, to find the Air Change Rate (ACH):

We calculate the Volume of the given space:

V_{s} = A_{s}\times h = 100\times 10 = 1000 ft^{3}

Now, the ACH per min:

= \frac{V_{s}}{Q_{a}} = \frac{1000}{200} = 5/min

Now, ACH per hour:

= \frac{60}{5} = 12/h

3 0
4 years ago
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