Answer:
Qcd=0.01507rad
QT= 0.10509rad
Explanation:
The full details of the procedure and answer is attached.
Air,in a piston cylinder assembly, is initially at 300 K and 200 kPa.It is then heated at constant pressure to 600 K. Determine
the change in internal energy of air per unit mass, using:
a) The ideal gas table for air.b) Show the process on a (p-v) diagram.
a) The ideal gas table for air.b) Show the process on a (p-v) diagram.
2 answers:
You might be interested in
Answer:
heat loss per 1-m length of this insulation is 4368.145 W
Explanation:
given data
inside radius r1 = 6 cm
outside radius r2 = 8 cm
thermal conductivity k = 0.5 W/m°C
inside temperature t1 = 430°C
outside temperature t2 = 30°C
to find out
Determine the heat loss per 1-m length of this insulation
solution
we know thermal resistance formula for cylinder that is express as
Rth = .................1
here r1 is inside radius and r2 is outside radius L is length and k is thermal conductivity
so
heat loss is change in temperature divide thermal resistance
Q =
Q =
Q = 4368.145 W
so heat loss per 1-m length of this insulation is 4368.145 W