1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesnalui [34]
2 years ago
9

Explain the concept of energy conversion as applied to the generation of electricity also known as electrical energy​

Engineering
1 answer:
Allisa [31]2 years ago
5 0

Answer:

Electrical energy is energy derived as a result of movement of electrons. When used loosely, electrical energy refers to energy that has been converted from electric potential energy. ... Once converted from potential energy, electrical energy can always be called another type of energy (heat, light, motion, etc.)

Explanation:

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>helpful</em><em> </em><em>for</em><em> </em><em>you</em><em> </em></h2><h2><em>keep</em><em> </em><em>smiling</em><em> </em></h2>
You might be interested in
Which of these are not referenced in an assembly?
Otrada [13]
E. Parts they don’t resemble
7 0
2 years ago
As a general rule of thumb, in-line engines are easier to work on than the other cylinder arrangements.
siniylev [52]

Answer:

The general rule of thumb is that the SMALLER a substance's atoms and the STRONGER the bonds, the harder the substance. Two of the strongest forms of chemical bonds are the ionic and covalent bonds.

Explanation:

5 0
2 years ago
Fill in the blank to correctly complete the statement below.
ZanzabumX [31]
Did not engineer cables factoring wind shear
4 0
3 years ago
A pump is used to extract water from a reservoir and deliver it to another reservoir whose free surface elevation is 200 ft abov
babunello [35]

Answer:

a) the expected flow rate is 31.4 ft³/s

b) the required brake horsepower is 2808.4 bhp

c) the location of pump inlet to avoid cavitation is -8.4 ft

Explanation:

Given the data in the question;

free surface elevation = 200 ft

total length of pipe required = 1000 ft

diameter = 12 inch

Iron with relative roughness ( k/D ) = 0.0005

H_{pump = 665-0.051Q² [Qinft ]

a) the expected flow rate

given that;

k/D  = 0.0005

k/2R = 0.0005

R/k = 1000

now, we determine the friction factor;

1/√f = 2log₁₀( R/k ) + 1.74

we substitute

1/√f = 2log₁₀( 1000 ) + 1.74

1/√f = 6 + 1.74

1/√f = 7.74

√f = 1/7.74

√f = 0.1291989

f = (0.1291989)²

f = 0.01669

Now, Using Bernoulli theorem between two reservoirs;

(p/ρq)₁ + (v²/2g)₁ + z₁ + H_p = (p/ρq)₂ + (v²/2g)₂ + z₂ + h_L

so

0 + 0 + 0 + 665-0.051Q² = 0 + 0 + 200 + flQ²/2gdA²

665-0.051Q² = 200 + flQ²/2gdA²

665-0.051Q² = 200 +[  ( 0.01669 × 1000 × Q² ) / (2 × 32.2 × (π/4)² × 1⁵ )

665 - 0.051Q² = 200 + [ 16.69Q² / 39.725 ]

665 - 200 - 0.051Q² = 0.420138Q²

665 - 200 = 0.420138Q² + 0.051Q²

465 = 0.471138Q²

Q² = 465 / 0.471138

Q² = 986.97196

Q = √986.97196

Q = 31.4 ft³/s

Therefore, the expected flow rate is 31.4 ft³/s

b) the brake horsepower required to drive the pump (assume an efficiency of 78%).

we know that;

P = ρgH_pQ / η

where; H_p = 665 - 0.051(986.97196) = 614.7

we substitute;

P = ( 62.42 × 614.7 × 31.4 ) / ( 0.78 × 550 )

P = 1204804.6236 / 429

P = 2808.4 bhp

Therefore, the required brake horsepower is 2808.4 bhp

c) the location of pump inlet to avoid cavitation (assume the required NPSH=25 ft).

NPSH = (P_{atom / ρg) - h_s - ( P_v / ρg )

we substitute

25  = ( 2116 / 62.42 ) - h_s - ( 30 / 62.42 )

h_s = 8.4 ft

Therefore, the location of pump inlet to avoid cavitation is -8.4 ft

6 0
2 years ago
You decide to use a battery labeled “850 mAh 2S” with a total voltage of 7.4 V. What is the overall energy capacity of the batte
kati45 [8]

Given Information:

Ampere-hour of battery = 850 mAh

Voltage of battery = 7.4 V

Required  Information:

Overall energy Capacity of battery = ?

Answer:

Overall energy Capacity of battery = 22.64 kJ

Explanation:

The overall energy capacity of the battery is found by

Energy = Ah*Voltage*3600

Convert mili-Ampere-hour into Ampere-hour

850/1000 = 0.85 Ah

Energy = 0.85*7.4*3600

Energy = 22,644 J

or

Energy = 22.64 kJ

Therefore, the overall energy capacity of the battery in Joules is 22.64 kJ

Note:

The factor 3600 is used since there are 60*60 seconds in 1 hour

Charge = current*time

Energy = voltage*charge  

Energy = current*voltage*time

3 0
3 years ago
Other questions:
  • Write a function named "read_prices" that takes one parameter that is a list of ticker symbols that your company owns in their p
    14·1 answer
  • Two forces, one of which double the other has resultant of 280N. if the direction of the large force is reversed and the remaini
    6·1 answer
  • Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. A divisor is a numb
    10·1 answer
  • How is the fuel introduced into the Diesel engine?
    9·1 answer
  • Define Plastic vs elastic deformation.
    13·1 answer
  • A Toyota Camry of mass 1650 kg turns from Chaplin Road to Route 79, thereby accelerating from 35 MPH in the city till 70 MPH on
    6·1 answer
  • Consider a 0.15-mm-diameter air bubble in a liquid. Determine the pressure difference between the inside and outside of the air
    10·1 answer
  • Any help is appreciated &lt;3
    14·1 answer
  • An op-amp differential amplifier is built using four identical resistors, each having a tolerance of ±5%. Calculate the worst p
    14·1 answer
  • Technician A says that 5W-30 would be better to use than 20W-50 in most vehicles in
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!