Answer:
a) 6.4 mg/l
b) 5.6 mg/l
Explanation:
Given data:
effluent Discharge Q_w = 1.0 m^3.s
Ultimate BOD L_w = 40 mg/l
Discharge of stream Q_r = 10 m^3.s
Stream ultimate BOD L_r = 3 mg/l
a) Ultimate BOD of mixture
b) utlimate BOD at 10,000 m downstream
putting
t = 0.578 days
we know
Answer:
Your question lacks the time required hence i will calculate the Average flow rate using a general concept and an assumed time value of 25 seconds
ANSWER : 104.904 ft^3/sec
Explanation:
General concept : Average flow rate is the volume of fluid per unit time through an area
Hence the average flow rate of the air conditioning unit of this room
Volume of the room / time taken for the air to cycle the room = v / t
assuming the time taken = 25 seconds
volume of room = width * length * height
= 14.1 * 15.5 * 12 = 2622.6 ft^3
Average flow rate = V/ t
= 2622.6 / 25 = 104.904 ft^3/sec
Answer:
Tech A is correct
Explanation:
Tech A is right as its V- angle is identified by splitting the No by 720 °. Of the piston at the edge of the piston.
Tech B is incorrect, as the V-Angle will be 720/10 = 72 for the V-10 motor, and he says 60 °.