Answer:
second-law efficiency = 62.42 %
Explanation:
given data
temperature T1 = 1200°C = 1473 K
temperature T2 = 20°C = 293 K
thermal efficiency η = 50 percent
solution
as we know that thermal efficiency of reversible heat engine between same temp reservoir
so here
efficiency ( reversible ) η1 = 1 -
............1
efficiency ( reversible ) η1 = 1 -
so efficiency ( reversible ) η1 = 0.801
so here second-law efficiency of this power plant is
second-law efficiency =
second-law efficiency =
second-law efficiency = 62.42 %
Answer:
u could get hurt or it could not sence in but it easy to work with and u can just relax till u get were ur going.
Explanation:
Answer:
The answer is "828.75"
Explanation:
Please find the correct question:
For W21x93 BEAM,

For A992 STREL,

Check for complete section:

Design the strength of beam =

15x -/c/ fb is the answer