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GREYUIT [131]
2 years ago
5

PLEASE ANSWER ASAP FOR BRAINLEST SUPER EASY QUESTION!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
GenaCL600 [577]2 years ago
7 0

Answer:

26.8

Step-by-step explanation:

you round up 5 and make the 7 an 8

Morgarella [4.7K]2 years ago
6 0

Answer:

26.8

Step-by-step explanation:

The number after the decimal is the "tenth" and any number that is five or larger, you would round up. The number to the right of the tenth is 0.05 which is equal to five so you would round up. Hence the answer 26.8

You might be interested in
Does a=2.1 b=7.2 c=7.5 form a right triangle
Anna007 [38]

Answer:

Yes

Step-by-step explanation:

If the longest side squared is equal to the sum of the squares on the other 2 sides then they form a right triangle

longest side = 7.5

7.5² = 56.25

2.1² + 7.2² = 4.41 + 51.84 = 56.25

Thus the 3 values form a right triangle.

6 0
3 years ago
Read 2 more answers
11) The function: f(x)= x^2 – 2x + 3 belongs to<br> which family of functions?
Dmitrij [34]

Answer:

i believe a quadratic function

Step-by-step explanation:

quadratics are when an equation is x^2 so yeah (sorry if thats not what it's asking)

7 0
3 years ago
Plsss help me, ASAP, Thank you
ankoles [38]

Answer:

\frac{1}{16}  \frac{10}{9}

Step-by-step explanation:

a reciprocal is a number that when multiplied by a given number gives 1 as  product.

16 * x = 1

x = 1/16

9/10 * x = 1

x = 10/9

8 0
3 years ago
Read 2 more answers
Given h(x) = 5x + 2, solve for a when h(x) = -8.
Whitepunk [10]

Answer:

i think its -38

Step-by-step explanation:

3 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
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