Answer:
A) 200 j
B) 0 J
C) -100 J
D) -300 J
Explanation:
We know that change in potential energy is given as
where, mg is weight
yf and yi final and initial position
mg = 10 N
yf = 0 m
yi = 20 m
B) mg = 10 N
yf = 20 m
yi = 20 m
c) before fall from the drone
U = mgh
h = yf - yi = 20 - 30 = -10 m
D) point has 0 potential energy
mg = 10 N
h = yf -yi = 0 -30 = - 30 m
Let
dV = dt = water is flowing in at a rate of 12 ft3 / min.
h = the depth of the water.
dh / dt = the rate of change of the depth.
First you must find the volume of the cone as a function of "h". Then you must derive the volume of the cone with respect to time. Finally clear dh / dt.
I attach the solution.
Answer:
3
Explanation:
You must first make sure the equation is balanced. This one is. Then, you simply add up the coefficients of each compound on the products side of the equation. When the coefficient is not specified, you can assume it is 1 mole. So, in this equation, there is 1 mole of CaCl₂, 1 mole of CO₂, and 1 mole of H₂O = 3 moles.
The reactant side of the equation also has three moles:
1 mole of CaCO₃ and 2 moles of HCl.
Given that,
Length of bar = 600 mm
Diameter of bar = 40 mm
Diameter of hole = 30 mm
Length of hole = 100 mm
Modulus of elasticity = 85 GN/m²
Load = 180 kN
We need to calculate the area of cross section without hole
Using formula of area
Put the value into the formula
We need to calculate the area of cross section with hole
Using formula of area
Put the value into the formula
We need to calculate the total contraction on the bar
Using formula of total contraction
Total contraction = contraction in bar without hole part + contraction in bar with hole part
Where, F = load
L = length
A = area of cross section
E = modulus of elasticity
Put the value into the formula
Hence, The total contraction on the bar is 1.227 mm²