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stealth61 [152]
3 years ago
12

Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?

Physics
2 answers:
morpeh [17]3 years ago
8 0

Answer:

C. Elements with intermediate number of valence electrons are the most chemically stable.

BabaBlast [244]3 years ago
3 0

Answer:

A. Elements with intermediate numbers of valence electrons are the last chemically stable.

Explanation:

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macmillan learning im Hamm at big bend Coty Conege A 1.30-m-long rope is stretched between two points with a tension that makes
san4es73 [151]

Answer:

0.87 m

70.6 Hz

Explanation:

L = length of the rope = 1.30 m

n = order of the harmonic = 3

\lambda = Wavelength

Wavelength is given as

\lambda = \frac{2L}{n}

\lambda = \frac{2(1.30)}{3}

\lambda = 0.87 m

v = Speed of transverse wave = 61.4 m/s

f = frequency of the third harmonic

frequency is given as

f = \frac{v}{\lambda }

f = \frac{61.4}{0.87}

f = 70.6 Hz

5 0
3 years ago
A vertical piston-cylinder device initially contains 0.1 m^3 of air at 400 K and 100 kPa. At this initial condition, the piston
jenyasd209 [6]

Answer:

Q=-38.15kJ

Explanation:

From the question we are told that

Piston-cylinder initial Volume of air v_1=0.1 m^3

Piston-cylinder initial temperature T_1=400k

Piston-cylinder initial pressure P_1= 100kpa

Supply line temperatureT_s=400k

Supply line pressure P_s= 500kpa

Valve  final pressure P_v=500kpa

Piston movement pressure P_m=200kpa

Piston-cylinder final Volume of airv_2=0.2 m^3

Piston-cylinder final temperature T_2=440k

Piston-cylinder final pressure P_2= 500kpa

Generally the  equation for conservation of mass is mathematically given by

Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h

where

Initial moment

m_1=\frac{p_1 V_1}{RT_1}

m_1=\frac{100*0.1}{0.287*400}

m_1=8.7*10^-^2kg

Final moment

m_2=\frac{p_2 V_2}{RT_2}

m_1=\frac{500*0.3}{0.287*440}

m_1=79*10^{-2}kg

Work done by Piston movement pressure

W=Pd

W=P(v_2-v_1)

W=200(0.2-0.1))

W=20000J

Heat function

h=cT_1

h=1.005(400)

h=402

Therefore

Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))

Q=-38.15kJ

It is given mathematically that the system lost  or dissipated Heat of

Q=-38.15kJ

7 0
3 years ago
A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:
Alex

Answer:

The work done on the system can be accounted for by;

Both E_g and E_{int}

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, F_{NET} = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = E_g

The heat generated as internal energy to the system = E_{int}

Therefore;

The work done on the system = E_g + E_{int}.

6 0
3 years ago
If a person is throwing darts at a target, and shoots three in a row in the same spot on the 20 section outer ring, but none in
Gwar [14]
a) precise but not accurate. 

this is because the thrower was capable to repeat the same result everytime but it was not the desire outcome.
6 0
3 years ago
Read 2 more answers
Which SPF level should a person look for in sunscreen as part of planning a day at the beach? pls i need it now
slega [8]

30

Hope you do well on the test and hope this helps!

3 0
4 years ago
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