Answer:
Day 2
Step-by-step explanation:
Every 20 days, one jar is full.
To find when it was 1/8 full, we multiply the 20 days by 1/8.
20 x 1/8 = 2
Day 2
Answer:
what
Step-by-step explanation:
⣿⣷⡁⢆⠈⠕⢕⢂⢕⢂⢕⢂⢔⢂⢕⢄⠂⣂⠂⠆⢂⢕⢂⢕⢂⢕⢂⢕⢂ ⣿⣿⣿⡷⠊⡢⡹⣦⡑⢂⢕⢂⢕⢂⢕⢂⠕⠔⠌⠝⠛⠶⠶⢶⣦⣄⢂⢕⢂⢕ ⣿⣿⠏⣠⣾⣦⡐⢌⢿⣷⣦⣅⡑⠕⠡⠐⢿⠿⣛⠟⠛⠛⠛⠛⠡⢷⡈⢂⢕⢂ ⠟⣡⣾⣿⣿⣿⣿⣦⣑⠝⢿⣿⣿⣿⣿⣿⡵⢁⣤⣶⣶⣿⢿⢿⢿⡟⢻⣤⢑⢂ ⣾⣿⣿⡿⢟⣛⣻⣿⣿⣿⣦⣬⣙⣻⣿⣿⣷⣿⣿⢟⢝⢕⢕⢕⢕⢽⣿⣿⣷⣔ ⣿⣿⠵⠚⠉⢀⣀⣀⣈⣿⣿⣿⣿⣿⣿⣿⣿⣿⣗⢕⢕⢕⢕⢕⢕⣽⣿⣿⣿⣿ ⢷⣂⣠⣴⣾⡿⡿⡻⡻⣿⣿⣴⣿⣿⣿⣿⣿⣿⣷⣵⣵⣵⣷⣿⣿⣿⣿⣿⣿⡿ ⢌⠻⣿⡿⡫⡪⡪⡪⡪⣺⣿⣿⣿⣿⣿⠿⠿⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠃ ⠣⡁⠹⡪⡪⡪⡪⣪⣾⣿⣿⣿⣿⠋⠐⢉⢍⢄⢌⠻⣿⣿⣿⣿⣿⣿⣿⣿⠏⠈ ⡣⡘⢄⠙⣾⣾⣾⣿⣿⣿⣿⣿⣿⡀⢐⢕⢕⢕⢕⢕⡘⣿⣿⣿⣿⣿⣿⠏⠠⠈ ⠌⢊⢂⢣⠹⣿⣿⣿⣿⣿⣿⣿⣿⣧⢐⢕⢕⢕⢕⢕⢅⣿⣿⣿⣿⡿⢋⢜⠠⠈ ⠄⠁⠕⢝⡢⠈⠻⣿⣿⣿⣿⣿⣿⣿⣷⣕⣑⣑⣑⣵⣿⣿⣿⡿⢋⢔⢕⣿⠠⠈ ⠨⡂⡀⢑⢕⡅⠂⠄⠉⠛⠻⠿⢿⣿⣿⣿⣿⣿⣿⣿⣿⡿⢋⢔⢕⢕⣿⣿⠠⠈ ⠄⠪⣂⠁⢕⠆⠄⠂⠄⠁⡀⠂⡀⠄⢈⠉⢍⢛⢛⢛⢋⢔⢕⢕⢕⣽⣿⣿⠠⠈
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Answer:
you add your number and then you subtract it so all the other steps are are going to be the exact same
We have that
<span>question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3
the answer is the option
</span><span>B: m2 + 10m3
</span><span>Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3
the answer is the option
</span><span>B: 8a3 + 6a2 − 7a + 3
</span><span>Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.
we have that
[</span>the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
<span>=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30
the answer is the option
</span><span>C: −0.03x2 + 6x + 30
</span><span>
</span>
9514 1404 393
Answer:
second step is wrong; x = 5
Step-by-step explanation:
The correct solution is ...
3(x -3) +9 = 15
3x -9 +9 = 15 . . . . . . . not 3x -3
3x = 15
x = 5
_____
Jeremy did what a lot of students do -- failed to apply the outside factor to <em>all</em> of the terms in parentheses.
