Answer:
position: (-6, -4)
range: 6
Step-by-step explanation:
The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.
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The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Matching parts of the equation, we find ...
h = -6, k = -4, r = √36 = 6.
Grayson's mistake was that he multiplied 4 and 3 and then used the exponent he had to square 3 and then multiply it by 4.
Emily's mistake was that she added 2 to 36 instead of multiplying it by -2
Pat's mistake was that he forget to make y into -2 instead of 2
The right way to do this is 4(3^2)+2(-2)
(3^2)=9 9×4=36 2(-2)=-4 -4+9=5
Hi
I belive you add the top side (4) plus the bottom side (9.5) witch would equal 13.5 times the hieght (3) equals 40.5 divided by 2 equals 20.25. the area is 20.25ft squared
another way to do it
4+9.5= 13.5
13.5×3= 40.5
40.5÷2= 20.25ft
Answer:
YES. (2, 7) is a solution of the system.
Step-by-step explanation:
System of linear inequalities has been given as,
y ≥ -x + 1 --------(1)
y < 4x + 2 ------(2)
If (2, 7) is a solution of the given system of inequalities, it will satisfy both the inequalities.
By substituting the coordinates of point (2, 7) in inequality (1),
7 ≥ -2 + 1
7 ≥ -1
True.
By substituting the coordinates of point (2, 7) in inequality (2),
7 < 4(2) + 1
7 < 9
True.
Therefore, point (2, 7) lie in the solution area of system of inequalities.
YES. (2, 7) is a solution of the system.
