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3 years ago

Plzzzzzz help what is the area of a triangle that is 21mm and 17mm

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

Answer:

$area = \frac{1}{2} \times 21 \times 17 \\ area = 178.5 {mm}^{2}$

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What indicators predict that a quadratic function will have a complex solution?

zysi [14]

The nature of the roots can be determined by the determinant of the equation. The determinant is:
b² - 4ac

If this is positive, there are two roots
If this is 0, there is only one root
If this is negative, there are complex roots

8 0

3 years ago

1.09 times 10 to the negative 3rd power

adoni [48]

Answer:

0.00109

Step-by-step explanation:

1.09(10^−3)

=1.09*10^−3

=1.09* 1 /10*10*10

=0.00109

5 0

3 years ago

Solve x. 10(2x - 4) = 100x

mr_godi [17]

Answer:

x=1/2

Step-by-step explanation:

Distribute the 10. it will be 20x-40=100x. Subtract 20x from both sides. it will be 40=80x. Divide by 80 to leave the x by itself. x=40/80...in simplify form....its 1/2

3 0

3 years ago

Please help quickly as possible please

zheka24 [161]

First we need to establish the fact that angles on a straight line ALWYS add up to 180
So, we solve the equation for x which turns out to be 3
But,were not done. The question asks us to find the value of the angle BOC
so we substitute the value of x into the equation for BOC (which is 6x+29)
And then your answer is 47 degrees

7 0

3 years ago

I’ll mark brainlest:( i need help!

enyata [817]

Answer: Choice A) $3 \sqrt{26}$

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Work Shown:

$\text{The two points are } (x_1,y_1) = (6,7) \text{ and } (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\$

$d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\$

When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule $\sqrt{x*y} = \sqrt{x}*\sqrt{y}$ to break up the root and simplify.

7 0

4 years ago