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VLD [36.1K]
3 years ago
14

Which of the following examples best demonstrates kinetic energy?

Chemistry
1 answer:
Vlada [557]3 years ago
4 0
Answer:-

Thanks for not describing your question well enough
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The period of an osciller is 2.34 minutes. What id the frequency of this oscillator in hertz?
AleksAgata [21]

Explanation:

Given parameters

Period = 2.34minutes

Unknown:

Frequency of the oscillator = ?

Solution:

Frequency is the number of waves that passes through a point at a given time. It is the inverse of period which is the time it takes for a wave to pass through a medium:

             F = \frac{1}{T}

F is the frequency

T is the period

      To solve this, convert the period to seconds:

              2.34minutes to seconds:

                1 min = 60seconds

              2.34 =  60 x 2.34 = 140.4s

F = \frac{1}{140.4} = 0.007hz or 0.007s⁻¹

Learn more:

frequency brainly.com/question/5882803

#learnwithBrainly

5 0
3 years ago
What is found in the outer region of the electron cloud
Alex Ar [27]
Valence electrons is the answer to ur question
4 0
3 years ago
Although there are different ways to approach a scientific investigation, all scientific investigations begin with some sort of
raketka [301]

Answer: hypothesis or guess

(pls mark me brainliest)

5 0
3 years ago
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What volume of 0.205 m k3po4 solution is necessary to completely react with 154 ml of 0.0110 m nicl2? 1.65 l?
sasho [114]
The balanced equation for the above reaction is 
2K₃PO₄   + 3NiCl₂  ---> 6KCl + Ni₃(PO₄)₂
stoichiometry of K₃PO₄  to NiCl₂ is 2:3
the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol
if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ 
then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³  = 1.13 x 10⁻³ mol of K₃PO₄
molarity of K₃PO₄ solution given - 0.205 M
there are 0.205 mol in 1 L
therefore 1.13 x 10⁻³ mol are in - 1.13 x 10⁻³ mol / 0.205 mol/L = 5.51 mL
volume of K₃PO₄ required - 5.51 mL
3 0
3 years ago
Questions
AlekseyPX

Answer:

the answer is convection

convection

6 0
3 years ago
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