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kaheart [24]
2 years ago
13

What is the abreviation for carbon dioxide??

Chemistry
1 answer:
Schach [20]2 years ago
4 0
CO2  is the abreviation for carbon dioxide.
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Electrons must be able to flow through a material in order for the material to conduct
djverab [1.8K]

The molecular structure of the solids has lower ability to conduct electricity due to tight holding by nucleus.

<h3>Why molecular solids are poor conductors?</h3>

Molecular solids are also poor conductors of electricity because their valence electrons are tightly held by the nuclear charges present in the nucleus while on the other hand, Metals are good electrical conductors in the solid form due to the presence of free electrons that helps in the conduction of electricity.

Learn more about electricity here: brainly.com/question/25144822

7 0
2 years ago
Julio earns $300 a week working a summer job. The paycheck he deposits in the bank is for $250. Which of these accounts for the
azamat

Answer:

theirs a $50 tax with the income hes making

Explanation:

5 0
2 years ago
Read 2 more answers
Each element consists of only one type of atom.<br> A.) True<br> B.) False
natima [27]
False there are different configurations of atoms called isotopes
7 0
2 years ago
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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
The best reading for the volume of the gas in the syringe in the picture shown right is
spayn [35]

Answer:

48.5 mL , just did it on edge

6 0
3 years ago
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