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scoray [572]
3 years ago
10

What is the 6th term in the geometric sequence described by this explicit formula?

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0
I think it’s 243 if it’s
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Hello! I don't understand how to do this question Triangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle
Katen [24]

ANSWER

EXPLANATION

Given that

X (-2, 1)

Y (-4, -3)

Z (0, -2)

The transformation rule of the triangle is given as

(x, y) ----------------> (x - 1, y + 3)

From, the given transformation rule, we can now find the new coordinates

X (-2, 1) --------------> X' (-2 -1, 1 + 3)

X(-2, 1 ----------------> X' (-3, 4)

Y(-4, -3) -----------------> Y'(-3-1, -3+1)

Y(-4, -3)-------------------> Y' (-4, -2)

Z(0, -2) --------------------Z'(0-1, -2+3)

Z(0, -2) -------------------> Z'(-1, 1)

Therefore the new coordinates of the triangles are

X' (-3, 4)

Y' (-4, - 2)

Z' (-1, 1)

8 0
1 year ago
What is the best estimate of 2π²?
Rasek [7]
2π^2=19.7392088 to 20 since 19.7392088 is closer to 20.
6 0
3 years ago
A company sells kitchen toys for kids, including artificial carrots that are cone shaped with a radius of 1 cm and a height of 6
sdas [7]

Answer:

Total space in the box is 75.2 cm³.

Step-by-step explanation:

Cone:

  • It is three dimension shape.
  • It has a vertex.
  • The slant height of a cone l^2=r^2+h^2, l= slant height, r= radius of the base, h= height
  • The lateral surface area is πrl
  • The volume of a cone is \frac13 \pi r^2h.

The artificial carrot that are cone shaped with a radius 1 cm and a height of 6 cm.

So, the volume of the cone is =\frac13 \pi r^2h

                                                =\frac13 \pi (1)^2.6

                                                =2\pi cm³

The volume 1 dozen carrots is = (12×2π)   cm³

                                                  =75.4 cm³

The volume of the box= The volume of the 1 dozen carrot.

Total space in the box is 75.2 cm³.

4 0
3 years ago
PLEASEEEEEEEEEE HELPPPPPPPPPPP
ankoles [38]

Answer:

I would just guess, but if i were to actually think about it, i would think C. I hope it helps, and blame it on me if you fail.

Step-by-step explanation:

8 0
3 years ago
Where are the x-intercepts for f(x) = −4cos(x − pi over 2) from x = 0 to x = 2π?
yKpoI14uk [10]
Recall that to get the x-intercepts, we set the f(x) = y = 0, thus

\bf \stackrel{f(x)}{0}=-4cos\left(x-\frac{\pi }{2}  \right)\implies 0=cos\left(x-\frac{\pi }{2}  \right)
\\\\\\
cos^{-1}(0)=cos^{-1}\left[ cos\left(x-\frac{\pi }{2}  \right) \right]\implies cos^{-1}(0)=x-\cfrac{\pi }{2}
\\\\\\
x-\cfrac{\pi }{2}=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}

\bf -------------------------------\\\\
x-\cfrac{\pi }{2}=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{2\pi }{2}\implies \boxed{x=\pi }\\\\
-------------------------------\\\\
x-\cfrac{\pi }{2}=\cfrac{3\pi }{2}\implies x=\cfrac{3\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{4\pi }{2}\implies \boxed{x=2\pi }
3 0
3 years ago
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