Given :
An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.
To Find :
the image height (in cm).
Solution :
By lens formula :
Here, u = - 100 cm
f = 150 cm
Now, magnification is given by :
Therefore, the image height is 3 m or 300 cm.
Answer:
The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.
Explanation:
By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:
Hydraulic Lift - Before change
Hydraulic Lift - After change
Where:
- Hydrostatic pressure, measured in pascals.
- Change in hydrostatic pressure, measured in pascals.
- Cross sectional area of the hydraulic lift, measured in square meters.
- Hydrostatic force, measured in newtons.
- Change in hydrostatic force, measured in newtons.
The additional weight is obtained after some algebraic handling and the replacing of all inputs:
Given that and
, the additional weight is:
The additional mass needed for the additional weight is:
Where:
- Additional weight, measured in newtons.
- Additional mass, measured in kilograms.
- Gravitational constant, measured in meters per square second.
If and
, then:
The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.
Answer:
The tension in the rope is 229.37 N.
Explanation:
Given:
Mass of the block is,
Coefficient of static friction is,
Angle of inclination is, °
Draw a free body diagram of the block.
From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.
Forces acting are and normal
. Now, there is no motion in the direction perpendicular to the inclined plane. So,
Consider the direction along the inclined plane.
The forces acting along the plane are and frictional force,
, down the plane and tension,
, up the plane.
Now, as the block is at rest, so net force along the plane is also zero.
Therefore, the tension in the rope is 229.37 N.
