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yulyashka [42]
3 years ago
5

Solve for a 1/2 a-9=11

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

a=31

Step-by-step explanation:

1/2(a-9)=11

a-9=22

a=22+9

a=31

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I know the answers but i need the work. plz help
inysia [295]
For number 3.

You add 8 to both sides as you need to separate the variable

4x-8=32
+8 +8

4x=32

now divide 32 by 4

x=8

for number 4

you use pemdas to multiply the parenthisis

2(x-5)=-20

(2•x)-(2•5)

2x-10=-20

then add 10 to both sides

2x-10=-20
+10 +10

2x=10

divide 10 by two

x=5


5 0
2 years ago
if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0
3 years ago
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Alexxx [7]
The answer is x is less than or equal to 3. the first answer choice
6 0
3 years ago
Read 2 more answers
30 gallons to 40 gallons​
Flura [38]

Answer:

10 or 70

Step-by-step explanation:

10= 40-30=10

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4 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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