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lina2011 [118]
3 years ago
12

If the x-value repeats and the y does not, is it a function?

Mathematics
1 answer:
kogti [31]3 years ago
7 0

Answer:

If X repeats and y does not it is not an example of a function. But if the y repeats and has two different x values that can be known as a function.

For an example ( 1 , 3) and (1, 4) thats not an example of a function because the x value is repeating but if its ( 1, 4) and (2,4) a thats

a function because no x value is repeating the x value is known as an independent value. Does that make sense?

"This relation is definitely a function because every x-value is unique and is associated with only one value of y. So for a quick summary, if you see any duplicates or repetitions in the x-values, the relation is not a function."

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Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have
Svet_ta [14]

Answer:

For 80 people, Elena would need

14 packs of plates and 10 packs of cups

She would have at least 80 of each.

I am not completely sure of this, sorry if wrong.

Step-by-step explanation:

80 people

8 cups per pack

6 plates per pack

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84

LCM (least common multiple) = 24

8 0
2 years ago
Read 2 more answers
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
What is the solution to the following system of linear equations?
Arturiano [62]

Answer:

i think it's B, no solutions

Step-by-step explanation:

because they are parallel to each other

3 0
2 years ago
Read 2 more answers
Given the function f(x)=x^4+8x^3+16x^2, determine all intervals on which f is decreasing.
ValentinkaMS [17]

Answer:

see attachment

Step-by-step explanation:

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3 years ago
You know 1000 mg = 1g. Convert 2.5 grams into milligrams. ​
Nuetrik [128]
The answer is 2500 milligrams
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3 years ago
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