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2 years ago

For a substance to change from a gas to a liquid the particles must _____

Chemistry

1 answer:

sveta [45]2 years ago

5 0

Answer:

The gas particles must touch a cold surface to start to slow down and get closer to form a liquid.

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Which of the following is a chemical change? Explain your reasoning: (a) boiling canned soup; (b) toasting a slice of bread; (c)

schepotkina [342]

Answer:

(d) burning a log.

(b) toasting a slice of bread;

Explanation:

Chemical change -

A chemical change refers to , the change in which a new compound is formed .

From the question ,

boiling canned soup ,

Its is not a chemical process , since no new compound is formed , these is only change in state as the liquid is turning to gaseous sate .

Chopping a log ,

It is not a chemical process , as no new substance is formed .

toasting a slice of bread

It is a chemical change , in which bread surface is deposited by a brown coat via the process of heating , even this process is a irreversible in nature .

burning of log ,

It is a chemical change , as with the help of heating , the wood is turning to ashes .

6 0

3 years ago

if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge

Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

5 0

3 years ago

There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc

zhuklara [117]

Answer:

$K_{sp}$ of $Zn(CH_{3}COO)_{2}$ is 0.0513

Explanation:

Solubility equilibrium of $Zn(CH_{3}COO)_{2}$ :

$Zn(CH_{3}COO)_{2}\rightleftharpoons Zn^{2+}+2CH_{3}COO^{-}$

Solubility product of $Zn(CH_{3}COO)_{2}$ ( $K_{sp}$ ) is written as- $K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}$

Where $[Zn^{2+}]$ and $[CH_{3}COO^{-}]$ represents equilibrium concentration (in molarity) of $Zn^{2+}$ and $CH_{3}COO^{-}$ respectively.

Molar mass of $Zn(CH_{3}COO)_{2}$ = 183.48 g/mol

So, solubility of $Zn(CH_{3}COO)_{2}$ = $\frac{43.0}{183.48}M$ = 0.234M

1 mol of $Zn(CH_{3}COO)_{2}$ gives 1 mol of $Zn^{2+}$ and 2 moles of $CH_{3}COO^{-}$ upon dissociation.

so, $[Zn^{2+}]$ = 0.234 M and $[CH_{3}COO^{-}]$ = $(2\times 0.234)M=0.468M$

so, $K_{sp}=(0.234)\times (0.468)^{2}=0.0513$

8 0

3 years ago

How many protons, neutrons, and electrons are in Ca-44?

Mariulka [41]

Protons = 20
Electron = 20
Neutrons = 20
Hope this Helps :)

4 0

3 years ago

Which one has a greatest mass, one atom of carbon, one atom of hydrogen, or one atom of litium

SpyIntel [72]

Lithium, it has an atomic number of about 3

5 0

3 years ago