Its $800 because to find interest u can use the formula I=PRT p is principal which is 500 times r which is rate-15/100(=15%) times 4
so the interest is 500×15/100×4=300
then u add 300 to 500 because the interest adds more money to the loan
Answer:
That would be 530.93
Step-by-step explanation:
There's no if about it,

has a zero

so

is a factor. That's the special case of the Remainder Theorem; since

we'll get a remainder of zero when we divide

by

At this point we can just divide or we can try more little numbers in the function. It doesn't take too long to discover

too, so

is a factor too by the remainder theorem. I can find the third zero as well; but let's say that's out of range for most folks.
So far we have

where

is the zero we haven't guessed yet. Again we could divide

by

but just looking at the constant term we must have

so

We check

We usually talk about the zeros of a function and the roots of an equation; here we have a function

whose zeros are
Answer:
See explanation below.
Step-by-step explanation:
Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.
A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.
Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.
Hope this helps! Have an Awesome Day!! :-)