Answer:
The correct answer to a) is sulfuric acid
b) 1/6 moles of aluminum sulfate is produced
Explanation:
To solve this we need to write out the balaned chemical equation as follows
Al(OH)3(s) + 3 H2SO4(aq) -----> Al2 (SO4)3(aq) + 6 H2O(l)
Here we see that one mole of aluminium hydroxide reacts with three moles of sulphuric acid to form one mole of aluminium sulphate and six ,oles of water
Hence the limiting reactant in this question is the sulphuric acid as 0.5 moles of alumininium hydroxide requires 1.5 moles of sulphuric acid to completely use up the aluminium hydroxide present
Dividing the number of moles of the reactants present by the amount of moles of sulphuric acid required we have
Hence 3 mole of sulphric acid combines with 1 mole of Aluminium hydroxide
0.5 mole of sulfuric acid combines with 0.5÷3 or 1/6 mole of Aluminium hydroxide
Hence the correct answer is sulfuric acid
b) to solve this, since three moles of sulfuric acid produces one mole of aluminium sulfate then 0.5 moles of sulfuric acid produces 0.5/3 or 0.166 mole of aluminum sulfate
hence 1/6 moles of aluminum sulfate is produced
Answer:
0.167
Explanation:
Molar mass of NaOH = 40
40 g of NaOH = 1 mole
5 g of NaOH = 0.125 moles
1000 ml = 1 L
750 ml = 0.75 L
Molarity = 0.125 / 0.75 = 0.1666
Approximately = 0.167
Answer:
your answer is b. chlorofluorocarbon(CFC
Explanation:
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Answer:
if you’re looking for a balanced equation it would be:
Methanol +ethanoic acid ==> methyl ethanoate + water ( in the presence of concentrated sulfuric acid )
CH3OH + CH3COOH==> CH3COOCH3 + H2O
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But, if you were looking for what it would be called it would be:
ethanoic acid with methanol will produce methyl ethanoate.
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And the reaction between Methanol and Ethanoic acid is known as esterification.
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I wasn’t sure of your question so I answered the best way that I could. I hope this helped!