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meriva
2 years ago
7

WILL GIVE EXTRA BRAINLST HAVE A NICE DAy

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer: 1.) Irrational (because its not terminal)

2.) 2^{2}

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Which goes where? Please help
Maurinko [17]

Answer:

first graph is negative

second is undefined

third is zero

fourth is positive

Step-by-step explanation:

If you plug it all in a calculator it will show

4 0
3 years ago
Here are two paint mixtures: • 3 cups of white and 4 cups of blue. • 6 cups of white and 8 cups of blue. Both mixtures make the
lesantik [10]

Answer:

The mixture that is an equivalent ratio is:

1.5 white 2 blue

Step-by-step explanation:

a) Data and Calculations:

Mixtures of the same color because they are in equivalent ratios:

3 cups of white and 4 cups of blue: equivalent ratio = 0.75: 1 (75%) since 3/4 = 75%

6 cups of white and 8 cups of blue. equivalent ratio = 0.75: 1 (75%) since 6/8 = 75%

Other mixtures:

5 cups white 6 blue: equivalent ratio = 0.83: 1 (83%) since 5/6 = 83%

1 white 1 1/2 blue: equivalent ratio = 0.67: 1 (67%) since 1/1.5 = 67%

4 white 3 blue: equivalent ratio = 1: 75 (1.33%) since 4/3 = 1.33%

1.5 white 2 blue: equivalent ratio = 0.75: 1 (75%) since 1.5/2 = 75%

Therefore, the mixture with equivalent ratio as the initial mixtures is 1.5 while 2 blue.

4 0
2 years ago
given : AD is ⊥to AB and DC, BC is ⊥ to AB and DC, angle EDC ≅ angle ECD, AD ≅ BC. prove: triangle ADE ≅ triangle BCE
Kamila [148]

Answer:

Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.

Step-by-step explanation:

Given:

AD ⊥ AB \& CD

BC ⊥ AB \& CD

AD = BC

∴ ∠ A = ∠ B = ∠ C = ∠ D =90°

∠ EDC = ∠ ECD

Solution

∠ C = ∠ BCE + ∠ ECD⇒ equation 1

∠ D = ∠ ADE + ∠ EDC⇒ equation 2

∠ C = ∠ D (given)

Substituting equation 1 and 2 in above equation we get

∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC

But ∠ EDC = ∠ ECD (given)

∴ ∠ ADE = ∠ BCE

ED = EC (∵ base angles are same triangle is isosceles triangle)

Now, In Δ ADE and Δ BCE

AD =BC

∠ ADE = ∠ BDE

ED = EC

∴ By Side Angle Side congruent property

Δ ADE ≅ Δ BCE

6 0
3 years ago
Enter the equation of the circle described below.<br><br> Center (3, -2), radius = 5
VMariaS [17]
Equation of a circle:
(x - h)^2 + (y - k)^2 = r^2

where (h,k) is the center and r = radius

(x - 3)^2 + (y + 2)^2 = 25
8 0
3 years ago
Question 2 is this a function? (2,4),(1,1),(0,0),(1,-1),(2,4)
Vadim26 [7]
No
there are multiple y values for 1 x(twice)
8 0
3 years ago
Read 2 more answers
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