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ycow [4]
4 years ago
5

Consider the equation StartFraction 5 Over 3 EndFraction v plus 4 plus StartFraction 1 Over 3 EndFraction v equals 8. v + 4 + St

artFraction 5 Over 3 EndFraction v plus 4 equals 8 minus StartFraction 1 Over 3 EndFraction v. v = 8. What is the resulting equation after the first step in the solution? v +4 = 8 – v StartFraction 4 Over 3 EndFraction v plus 4 equals 8.v +4 = 8 4 + v = 8 – 4 plus v equals 8 minus StartFraction 5 Over 3 EndFraction v.v 2v + 4 = 8

Mathematics
2 answers:
Monica [59]4 years ago
5 0

Answer:

the answer is d

Step-by-step explanation:

the first step is to put all the numbers that are similar together.

dalvyx [7]4 years ago
4 0

Answer:

The answer is d.

Step-by-step explanation:

Because,

5/3v+4+1/3v=8

so you have to combine like terms...

5/3v+1/3v=2v

so...

2v+4=8

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allochka39001 [22]

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6/7+3/5 simplest form
Sloan [31]

Answer:

\huge\boxed{\dfrac{6}{7}+\dfrac{3}{5}=\dfrac{51}{35}=1\dfrac{16}{35}}

Step-by-step explanation:

\dfrac{6}{7}+\dfrac{3}{5}\\\\\text{Find the}\ LCD-\text{Least Common Denominator}\\\\\text{List multiples of 7}:\ 0,\ 7,\ 14,\ 21,\ 28,\ \boxed{35},\ 42,\ ...\\\text{List multiples of 5:}\ 0,\ 5,\ 10,\ 15,\ 20,\ 25,\ 30,\ \boxed{35},\ 40,\ ...\\\\LCD(7,\ 5)=\boxed{35}\\\\35=7\cdot5

\dfrac{6}{7}+\dfrac{3}{5}=\dfrac{(6)(5)}{(7)(5)}+\dfrac{(7)(3)}{(7)(5)}=\dfrac{30}{35}+\dfrac{21}{35}=\dfrac{30+21}{35}=\dfrac{51}{35}=\dfrac{35+16}{35}=1\dfrac{16}{35}

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3 years ago
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Which is the percent composition of bromine in the compound nabr?
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We are given a compound known to be Sodium Bromine (NaBr). This compound has a molecular weight of
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