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ycow [4]
3 years ago
5

Consider the equation StartFraction 5 Over 3 EndFraction v plus 4 plus StartFraction 1 Over 3 EndFraction v equals 8. v + 4 + St

artFraction 5 Over 3 EndFraction v plus 4 equals 8 minus StartFraction 1 Over 3 EndFraction v. v = 8. What is the resulting equation after the first step in the solution? v +4 = 8 – v StartFraction 4 Over 3 EndFraction v plus 4 equals 8.v +4 = 8 4 + v = 8 – 4 plus v equals 8 minus StartFraction 5 Over 3 EndFraction v.v 2v + 4 = 8

Mathematics
2 answers:
Monica [59]3 years ago
5 0

Answer:

the answer is d

Step-by-step explanation:

the first step is to put all the numbers that are similar together.

dalvyx [7]3 years ago
4 0

Answer:

The answer is d.

Step-by-step explanation:

Because,

5/3v+4+1/3v=8

so you have to combine like terms...

5/3v+1/3v=2v

so...

2v+4=8

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Plz help u have to do all 3 parts
Jobisdone [24]

Answer:

all you have too do is 750*750 = 562,500

Step-by-step explanation:

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7 0
2 years ago
Slope of 2y = -x + 10
777dan777 [17]
The slope would be -1 because of the x
6 0
3 years ago
Read 2 more answers
I need help with this question
AlexFokin [52]
A
Find the two intersections of the lines. The value of x of the intersections will satisfy the system of equations.
Brainliest pls!
3 0
2 years ago
I need help on this question, thx and i will give brainliest to the first answer that's correct.
tensa zangetsu [6.8K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
The population of big cats in Africa is increasing at a rate of 5% per year. At the
sesenic [268]

Answer:

a) 10,500 big cats

b) 13,401 big cats

c) 33 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:  

A = P (1 + r) t  

Where:  

p = original population  

r = growing rate (decimal form; 5/100= 0.05)

t= years  

A = population after t years  

Replacing with the values given:  

a) At 2005, 1 year passed since 2004 (t=1)

A = 10,000 (1+ 0.05)^1

A = 10,500 big cats

b)

At 2010, 6 years passed since 2004 (2010-2004= 6)

A = 10,000 (1+ 0.05)^6

A = 13,401 big cats

c)

50,000 < 10,000 (1+ 0.05)^t

Solving for t:

50,000/10,000 < 1.05^t

5 < 1.05^t

log 5 < log 1.05^t

log 5 < t ( log 1.05)

log 5 / log 1.05 < t

32.9 years < t

33 years  = t

Feel free to ask for more if needed or if you did not understand something.  

6 0
3 years ago
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