Question

Which two values of x are roots of the polynomial below x^2+3x-5

Answer 1

Answer:

Step-by-step explanation:

Given a quadratic equation

ax^2+bx+c=0  

you can find its solutions with the following formula:

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}  

You equation is identified by the coefficients

x^2 - 3x + 5 \iff a = 1,\ b = -3,\ c = 5  

Which means the solutions are

\dfrac{3 \pm \sqrt{9-4\cdot 5}}{2} = \dfrac{3 \pm \sqrt{-11}}{2}

Answer 2

Answer:  the answers are B and D

Step-by-step explanation:

Because I have done this already :)