Question

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Answer 1

Answer:

2000 L

General Formulas and Concepts:

Atomic Structure

• Moles
• Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

• P is pressure
• V is volume (in L)
• n is number of moles
• R is gas constant
• T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

Step 2: Solve for V

1. Substitute in variables [Ideal Gas Law Formula]:                                           $\displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)$
2. Isolate V:                                                                                                           $\displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}$
3. Multiply/Divide [Cancel out units]:                                                                   $\displaystyle V = 1981.7 \ L$

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

1981.7 L ≈ 2000 L