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Tatiana [17]
3 years ago
9

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Chemistry
1 answer:
Neporo4naja [7]3 years ago
3 0

Answer:

2000 L

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles
  • Temperature Conversion: K = °C + 273.15

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • P is pressure
  • V is volume (in L)
  • n is number of moles
  • R is gas constant
  • T is temperature (in K)

Explanation:

<u>Step 1: Define</u>

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

<u>Step 2: Solve for </u><em><u>V</u></em>

  1. Substitute in variables [Ideal Gas Law Formula]:                                           \displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)
  2. Isolate <em>V</em>:                                                                                                           \displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}
  3. Multiply/Divide [Cancel out units]:                                                                   \displaystyle V = 1981.7 \ L

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1981.7 L ≈ 2000 L

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Answer:

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Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

= 100 g/mol

Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

=3.8/100

= 0.038 mol.

Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

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4 0
4 years ago
What would be the resulting molarity of a solution made by dissolving 21.9 grams of KCl in enough water to make an 869-millilite
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Molar mass KCl = <span>74.5513 g/mol

Number of moles:

21.9 / 74.5513 => 0.293 moles

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Molarity = moles / Volume

Molarity = 0.293 / 0.869

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4 years ago
The heat of vaporization of water is 40.66 kJ/mol. How much heat is absorbed when 3.11 g of water boils at atmospheric pressure?
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Answer:

The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.

Explanation:

A molar heat of vaporization of 40.66 kJ / mol means that 40.66 kJ of heat needs to be supplied to boil 1 mol of water at its normal boiling point.

To know the amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure, the number of moles represented by 3.11 g of water is necessary. Being:

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the molar mass of water is:

H₂O= 2* 1 g/mole + 16 g/mole= 18 g/mole

So: if 18 grams of water are contained in 1 mole, 3.11 grams of water in how many moles are present?

moles of water=\frac{3.11 grams*1 mole}{18 gramos}

moles of water= 0.1728

Finally, the following rule of three can be applied: if to boil 1 mole of water at its boiling point it is necessary to supply 40.66 kJ of heat, to boil 0.1728 moles of water, how much heat is necessary to supply?

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<u><em>The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.</em></u>

7 0
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2. Explain Charles law in terms of the kinetic<br> molecular theory?
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Answer:

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<span>When a plant goes through photosynthesis it produces oxygen as a waste product, which you should know is what animals use to breathe, well when animals use oxygen in the process, they also make a waste product which happens to be Carbon Dioxide, which a plant uses to make glucose during photosynthesis, so if we didin't have one we wouldn't have the other.

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