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maks197457 [2]
3 years ago
8

A dehydration reaction starting with 3.8 g cyclohexanol produces 2.6 g cyclohexene. Calculate the theoretical yield for this rea

ction. Report your answer with two significant figures.
Chemistry
1 answer:
diamong [38]3 years ago
4 0

Answer:

Theoretical yield of C6H10 = 3.2 g.

Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

= 100 g/mol

Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

=3.8/100

= 0.038 mol.

Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

Theoretical yield of C6H10 = 3.2 g

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I would say C. Since the material is getting warmer, the atoms and molecules will start to move fasten and then also create more "messiness" (which is entropy with a less-nice word)

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2 years ago
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2.25 g/ml at 700mmHg, 200 C. Find molar mass of gas.
Harrizon [31]

Answer:

Molar mass = 94972.745 g/mol

Explanation:

Given data:

Density = 2.25 g/ml

Pressure = 700 mmHg

Temperature = 200°C

Molar mass = ?

Solution:

Density = 2.25 g/ml (2.25×1000 = 2250 g/L)

Pressure = 700 mmHg (700/760 = 0.92 atm)

Temperature = 200°C (200+273 = 473K)

Formula:

d = PM/RT

M = dRT/P

M = 2250 g/L × 0.0821 atm.L /mol.K ×  473K / 0.92 atm

M = 87374.93 g/mol / 0.92

M = 94972.745 g/mol

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3 years ago
If you have a negative ion, what happened to the outer shell of the atom?
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It will lose them and become stable
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If it takes a force of 60 Newtons to move an elephant, then a person who supplies a force of 70 Newtons will be able to move it.
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2 years ago
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For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
2 years ago
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