Everything is composed of atoms<span>, which are the indivisible building blocks of matter and cannot be destroyed. hope this helped!!!!! :D
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1. 18 L
2. 20.832 L
<h3>Further explanation</h3>
Given
Combustion of ethane
Required
Volume of CO₂
Solution
Avogadro's Law :
In the same T,P and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
1. From equation, mol ratio of C₂H₆ : CO₂ ⇒ 2 : 6
so the volume of CO₂ :
= 6/2 x 6 L
= 18 L
2. mol ethane (MW=32 g/mol) :
= mass : MW
= 10 g : 32 g/mol
= 0.31
mol CO₂ :
= 6/2 x 0.31
= 0.93
The volume CO₂(assume at STP) = 20.832 L
Answer:
Catalyst is a substance that increases the rate of a chemical reaction but is chemically unchanged at the end of the reaction.
properties of catalyst :
1. A catalyst increases the speed of a reaction, and it also improves the yield of the intended product.
2. A catalyst actually takes part in the reaction even though it itself is not consumed or used up in the course of the reaction.
3. A catalyst makes the reaction faster by providing an alternative pathway with a lower activation energy.
4. A catalyst is reaction-specific. It may not be effective in another reaction even if the two reactions are of similar type.
5. In a reversible reaction, a catalyst accelerates both the forward and the reverse reactions. So, the inclusion of a catalyst does not alter the equilibrium constant of a reversible reaction.
Answer: 1739.6g
Explanation:
P1 = 7.04MPa
T1 = 25°C = 25 + 273 = 298K
n1 = 150mol
P2 = 2MPa
T2 = 19°C = 19 + 273 = 292K
n2 =?
n1T1/P1 = n2T2/P2
(150x298)/7.04 = (n2x292)/2
7.04xn2x292 = 150x298x2
n2 = (150x298x2) /(7.04x292)
n2 = 43.49moles
Molar Mass of Ar = 40g/mol
Mass = n x molar Mass = 43.49x40 = 1739.6g
Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:
If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of , because the molarity formula is:
In other words:
If we use the <u>atomic mass</u> of (19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:
Finally we can <u>divide by 1 L</u> to find the ppm:
<u>We will have a concentration of 607 ppm.</u>
I hope it helps!