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3 years ago

The mass of an object is 100 mg. What is the object's mass in kg?

2 answers:

7 0

0.0001 is the objects mass because you go from mili, to centi, deci, gram, deca, hecta, Kila. that's 6 decimal points which is what times you 3 zeroes before the 1. The decimal point started out at the end of 100 and moved 6 places to be 0.0001

nikdorinn [45]3 years ago

7 0

Answer:

100 mg is equal to 0.0001 kg

Explanation:

When doing conversions, you always need to remember the units you are working with. So when going from mg to kg, there are a lot of zeros to take into consideration.

1. mg to g:

When converting from milligrams to grams, you divide by 1000, because <u>there are 1000 milligrams in 1 gram</u>.

100 milligrams is equal to (100 ÷ 1000) grams

= 0.1 grams

2. Then converting g to kg:

When converting grams to kilograms, you once again divide by 1000, because <u>there are 1000 grams in 1 kilogram</u>.

0.1 grams is equal to (0.1 ÷ 1000) kilograms

= 0.0001 kilograms

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The substances sodium (Na), oxygen (O2), and sodium oxide (Na20) participate in this chemical reaction

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Answer:

Explanation:

This is a synthesis or a combination reaction , which involves the oxygen combining with sodium to make one compound.

hope it helps.

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3 years ago

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Answer:

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3 years ago

What is NOT a condition needed for a hurricane to form?

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The first condition is that ocean waters must be above 26 degrees Celsius (79 degrees Fahrenheit). Below this threshold temperature, hurricanes will not form or will weaken rapidly once they move over water below this threshold.

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3 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

Explanation:

Wavelength of the photon emitted = $\lambda =646.3 nm =646.3\times 10^{-9} m$

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

$E=\frac{hc}{\lambda }$

h = Planck's constant = $6.626\tiomes 10^{-34} Js$

c = Speed of the light = $3\times 10^8 m/s$

$E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}$

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3 years ago

1: At which temperature would a reaction withΔH = -102 kJ/mol, ΔS = -0.188 kJ/(mol×K) be spontaneous? 2: At which temperature wo

Naddik [55]

Answer:

1: At temperatures below 542.55 K

2: At temperatures above 660 K

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

$\Delta G=\Delta H-T\Delta S$

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

$0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K$

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

$0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K$

It means that at temperatures higher than 660 K the reaction will be spontaneous.

Best regards!

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2 years ago