The answer is the letter C
Answer:
I believe it is B,fluorine to complete the octet rule
Explanation:
Answer
Part A:
Given equation:

The above equation is an example of a double replacement reaction. A double replacement (or double displacement) reaction is a reaction in which the positive and negative ions of two ionic compounds exchange.
Note: The oxidation number of:
K = +1
I = -1
Ba = +2
S = -2
So, the complete chemical equation including phases of the given reaction is:

Part B:
Given equation:

Also, the equation is an example of a double replacement reaction.
Note: The oxidation number of:
K = +1
Cl = -1
Ca = +2
S = -2
The complete chemical equation including phases of the given reaction is:
Answer:
<h3>Density = 0.5 g/cm³</h3>
Explanation:
Density of a substance can be found by using the formula

From the question
mass = 32g
To find the density we must first find the volume of the block
From the question the block is a cuboid
Volume of cuboid = length × width × height
length = 8 cm
width = 4 cm
height = 2 cm
Volume of block = 8 × 4 × 2 = 64 cm³
Substitute the values into the above formula and solve for the density
That's....

We have the final answer as
Density = 0.5 g/cm³
The block will float because it's density is less than the density of water which is
1 g/cm³
Hope this helps you
KCO₂
K₂C₂O₄
Explanation:
Given parameters:
Percent composition:
K = 47%
C = 14.5%
O = 38.5%
Molar mass of compound = 166.22g/mol
Unknown:
Empirical formula of compound = ?
Molecular formula of compound = ?
Solution:
The empirical formula of a compound is its simplest formula. Here is how to solve for it:
K C O
Percent
composition 47 14.5 38.5
Molar mass 39 12 16
Number
of moles 47/39 14.5/12 38.5/16
moles 1.205 1.208 2.4
Dividing
by smallest 1.205/1.205 1.208/1.205 2.4/1.205
1 1 2
Empirical formula KCO₂
Molecular formula
This is the actual combination of the atoms:
Molecular formula = ( empirical formula of KCO₂)ₙ
Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol
n factor = 
n factor =
= 2
Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄
Learn more:
Empirical formula brainly.com/question/2790794
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