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marysya [2.9K]
3 years ago
14

Let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)

Mathematics
2 answers:
sammy [17]3 years ago
6 0

Answer:

12

Step-by-step explanation:

so basically

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped :)

photoshop1234 [79]3 years ago
3 0

The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.

Given functions are:

f(x) = x^2+2

g(x) = 1-3x

Now,

⇒ (fg) = (x^2+2)(1-3x)

By applying multiplication, we get

           =x^2+2-3x^3-6x

           =-3x^3+x^2-6x+2...(equation 1)

By substituting the value "-1" in place of "x" in equation 1, we get

⇒ (fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2

                  =-3(-1)+1+6+2

                  =3+1+6+2

                  =12

Thus the right answer is (fg)(-1) = 12.

Learn more:

brainly.com/question/10057660

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