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zavuch27 [327]
3 years ago
13

Why does carbon dioxide have a higher bond order than water?

Physics
2 answers:
finlep [7]3 years ago
8 0

Answer:

This is due to the stronger bond that forms between carbon and oxygen, which is greater than the bond between hydrogen and oxygen.

Explanation:

rusak2 [61]3 years ago
5 0

Answer:

<h3>Carbon dioxide has a higher bond order compared to water. This is due to the stronger bond that forms between carbon and oxygen, which is greater than the bond between hydrogen and oxygen.</h3>

hope it helps and brainliest if helped........

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1. A body has a velocity of 72 km/hr. Find its value in m/s.
CaHeK987 [17]

72 Km/hr

= 72000 m/ 60×60 s

= 72000 m/ 3600 s

= 20 m/s

Answer is 20 m/s.

Hope it helps! Please do comment

8 0
3 years ago
What pattern is seen on the moon from earth?
igomit [66]

If you mean pattern designs it’s rocky bumpy and you can see the circle patterns

If you mean phases the here’s a picture

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3 years ago
State keplers law........​
S_A_V [24]

Answer:

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its

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3 years ago
A radio wave has a frequency of 8.6 × 108 hz. what is the energy of one photon of this radiation (h = 6.63 × 10–34 j • s)?
My name is Ann [436]

Answer: 57.018\times10^{-26}J

Energy is directly proportional to the frequency.

The energy of a photon is given by:

E=h\nu

Where, E is the energy and \nu is the frequency.

Frequency of the radio wave is given:

\nu=8.6\times10^8 Hz

h=6.63\times10^{-34}J.s

Multiply the above two:

Energy,

E=h\nu=6.63\times10^{-34}J.s\times8.6\times10^8 Hz= 57.018\times10^{-26}J

Hence, the energy of each photon of radio wave having frequency  \nu=8.6\times10^8 Hz is 57.018\times10^{-26}J

5 0
3 years ago
Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8
guapka [62]
Hi, thank you for posting your question here at Brainly.

This problem could be solved using this equation:

Diffraction limit = 1.22*wavelength/diameter

diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m

Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
6 0
3 years ago
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