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3 years ago

Why does carbon dioxide have a higher bond order than water?

Physics

2 answers:

finlep [7]3 years ago

8 0

Answer:

This is due to the stronger bond that forms between carbon and oxygen, which is greater than the bond between hydrogen and oxygen.

Explanation:

rusak2 [61]3 years ago

5 0

Answer:

<h3>Carbon dioxide has a higher bond order compared to water. This is due to the stronger bond that forms between carbon and oxygen, which is greater than the bond between hydrogen and oxygen.</h3>

hope it helps and brainliest if helped........

You might be interested in

Give an example of a measurement that is precise to the nearest tenth of a gram.

Svet_ta [14]

Answer:

So we have a measure in grams, we can start with something like:

143.523 grams.

Now we want this measurement to be precise to the nearest tenth of a gram.

The nearest tenth of a gram is the first digit after the decimal point, then the digits that come after this are not useful, because they are outside our precision range.

Then we must write our measurement as:

143.5 grams

Where the digit that came after the 5 was a 2, so we rounded down.

4 0

3 years ago

A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s. Assuming the diameter of a tire is 58.0 cm, (a)

Virty [35]

Answer:

Explanation:

Given:

Initial velocity, u = 0 m/s (at rest)

Final velocity, v = 22 m/s

Time, t = 9 s

Diameter, d = 58 cm

Radius, r = 0.29 m

Using equation of motion,

v = u + at

a = (22 - 0)/9

= 2.44 m/s^2

v^2 = u^2 + 2a × S

S = (22^2 - 0^2)/2 × 2.44

= 99.02 m

S = r × theta

Theta = 99.02/0.29

= 341.44 °

1 rev = 360°

341.44°,

= 341.44/360

= 0.948 rev

= 0.95 rev

Final angular speed, wf = v/r

= 22/0.29

= 75.86 rad/s

6 0

3 years ago

In an a.c generator, there are rings used. What are there names and how are they adapted to reversing current.

djyliett [7]

Answer:

In an a.c generator, slip rings are used.

Adaptation: They are not directly connected directly to carbon brushes, hence donot come into contact when the rectangular coil rotates.

Explanation:

$.$

6 0

3 years ago

Read 2 more answers

Two footballs (A & B) are thrown with the same amount of force. Football A has a greater mass. Describe the acceleration for

Sauron [17]

Newton's second law gives the relationship between force applied to an object, its mass and its acceleration:
$F=ma$
where F is the force, m the mass and a the acceleration.

A force F is applied to football A, whose mass is $m_A$ , and so the acceleration of this football will be given by (re-arranging the previous equation)
$a_A = \frac{F}{m_A}$

Similarly, the acceleration of football B will be
$a_B= \frac{F}{m_B}$
where $m_B$ is the mass of football B, and where the force F applied to the two footballs is the same.

Since football A has greater mass than football B, $m_A \ \textgreater \ m_B$ , if we compare the two previous formula we see that the acceleration of football B is greater than the acceleration of football A:
$a_B \ \textgreater \ a_A$
Therefore, if the same force is applied to the two footballs, football B will accelerate more than football A.

8 0

3 years ago

In a glider stunt at an air show, a towing airplane (motorized plane pulling the gliders) takes off from a level runway with two

irakobra [83]

Answer:

minimum length of runway is needed for take off 243.16 m

Explanation:

Given the data in the question;

mass of glider = 700 kg

Resisting force = 3700 N one one glider

Total resisting force on both glider = 2 × 3700 N = 7400 N

maximum allowed tension = 12000 N

from the image below, as we consider both gliders as a system

Equation force in x-direction

2ma = T -f

a = T-f / 2m

we substitute

a = (12000 - 7400 ) / (2 × 700 )

a = 4600/1400

a = 3.29 m/s²

Now, let Vf be the final speed and Ui = 0 ( as starts from rest )

Vf² = Ui² + 2as

solve for s

Vf² = 0 + 2as

2as = Vf²

s = Vf² / 2a

given that take of speed for the gliders and the plane is 40 m/s

we substitute

s = (40)² / 2×3.29

s = 1600 / 6.58

s = 243.16 m

Therefore, minimum length of runway is needed for take off 243.16 m

4 0

3 years ago