Answer:
tension far end 883.055714 N
tension closer 578.634286 N
Explanation:
Given data
scaffold mass m1 = 64 kg
scaffold length L1 = 6.3 m
window washer mass m2 = 85 kg
distance L2 = 2 m
to find out
tension near cable and farther cable
solution
torques at the end farthest
(m1 × g × L1 ) / 2 + (m2 × g × L1- L2 ) = T × L1
T × 6.3 = (64 × 9.81 × 6.3 ) / 2 + (85 × 9.81 × 4.3 )
T = 5563.251 / 6.3
tension = 883.055714 N
and
torques at the other end,
(m1 × g × L1 ) / 2 + (m2 × g × L2 ) = T × L1
T × 6.3 = (64 × 9.81 × 6.3 ) / 2 + (85 × 9.81 × 2 )
T = 3645.396 / 6.3
tension = 578.634286 N
Answer:
So the conclusion is that in presence of air net force acting downward reduces for feather and hence falls slower than coin. But in absence of air resistance, net downward force is just equal to force due to gravity which is same for both coin and feather and hence they fall down at the same rate.
Answer:
one half as large , initial velocity is two times larger
Explanation:
Momentum is conserved.
p₁ + p₂ = p₁' + p₂'
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁ = m₂ =m , v₂= 0
v₁' =v₂'
mv₁ = 2mv₁'
v₁ = 2v₁'
Answer:
125 Joules
Explanation:
In an elastic motion, the net kinetic energy of the system is conserved i.e the total kinetic energy of the system after the collision is equal to the total kinetic energy of the system before collision;
Kinetic Energy = 1/2 m*v^2
Total Kinetic energy = Kinetic Energy(Cart 1) + Kinetic energy(Cart 2);
Total K.E = 0.5*(10)*(5)^2 + 0 = 125 Joules;
Energy after collision = Energy before collision = 125 joules