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3 years ago

How are cells alike but different?

1 answer:

6 0

They all make up living things-- but they're diverse (like plant and animal cells). The most basic differences between cells are their organelles. Like how an animal cell doesn't have a cell wall, but a plant cell does. Or their shapes, even. Plant cells are like boxes or rooms and animals cells are circular and less rigid.

There are a number of similarities and differences between cells. Hope this helps.

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A crumb of bread, of mass 0.056 kg, is pulled upon by ants from rival anthills. They exert the following forces: 0.06 N to the n

Valentin [98]

Answer:

a) 1.855m/s^2, 9.71\° to the east-north

b) 0.103N, 9.46° to the west-south

Explanation:

To find the acceleration of the system you can assume that the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

$0.06N-0.06Nsin(45\°)=ma_y\\\\0.08N-0.02N+0.06cos(45\°)=ma_x$

m: mass of the crumb of bread = 0.056kg

you simplify the equations an replace the values of the mass in order to obtain the acceleration components:

$a_y=\frac{0.017N}{0.056kg}=0.313\frac{m}{s^2}\\\\a_x=\frac{0.102N}{0.056kg}=1.829\frac{m}{s^2}$

$\theta=tan^{-1}(\frac{0.313}{1.829})=9.71\°\\\\a=\sqrt{a_x^2+a_y^2}=\sqrt{(1.829)^2+(0.313)^2}\frac{m}{s^2}=1.855\frac{m}{s^2}$

then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north

The fifth force must cancel both x an y components of the previous net force, that is:

$0.06N-0.06Nsin(45\°)+F_y=0\\\\F_y=-0.017N\\\\0.08N-0.02N+0.06cos(45\°)+F_x=0\\\\F_x=-0.102N\\\\\phi=tan^{-1}(\frac{-0.017}{-0.102N})=9.46\°$

$F=\sqrt{(0.102)^2+(0.017)^2}N=0.103N$

the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south

4 0

3 years ago

A 2100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5.00 m before coming into contact w

aliya0001 [1]

Answer:

f = 878,080 N

Explanation:

mass of pile driver (m) = 2100 kg

distance of pile driver to steel beam (s) = 5 m

depth of steel driven (d) = 12 cm = 0.12 m

acceleration due to gravity (g0 = 9.8 m/s^{2}

calculate the average force exerted on the pile driver by the beam.

from work done = force x distance

work done = change in potential energy of the pile driver

equating the two equations above we have

force x distance = m x g x (s - d)

f x 0.12 = 2100 x 9.8 x (5- (-0.12))

d = - 0.12 because the steel beam went down at we are taking its

initial position to be an origin point which is 0

f = ( 2100 x 9.8 x (5- (-0.12)) ) ÷ 0.12

f = 878,080 N

4 0

3 years ago

Explain why the bright spectral lines of light emitted from the atoms of an element are unique to that element

eduard

<span>If you want the Lewis diagram of arsenic, it is a single element, and not much of a "structure". Simply place five dots on the four sides of an imaginary square around the symbol As. Two of the dots are paired, three are unpaired.

</span>

4 0

3 years ago

Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$