Answer:
magnitude of the frictional torque is 0.11 Nm
Explanation:
Moment of inertia I = 0.33 kg⋅m2
Initial angular velocity w° = 0.69 rev/s = 2 x 3.142 x 0.69 = 4.34 rad/s
Final angular velocity w = 0 (since it stops)
Time t = 13 secs
Using w = w° + §t
Where § is angular acceleration
O = 4.34 + 13§
§ = -4.34/13 = -0.33 rad/s2
The negative sign implies it's a negative acceleration.
Frictional torque that brought it to rest must be equal to the original torque.
Torqu = I x §
T = 0.33 x 0.33 = 0.11 Nm
Answer:
No, distance is more important.
Answer:
Explanation:
a) Magnification = image height / object height = -9 / 18 = -0.5
b) Magnification = - image distance / object distance = -0.5
so image distance = 0.5 object distance
1/focal length = 1/image distance + 1/object distance
1/6 = 1/(0.5 object distance) + 1/object distance
object distance = 18.0 cm
c) Image appears behind the lens.
Answer:
<h2>3</h2>
Explanation:
Using the efficiency formula. Efficiency = MA/VR * 100%
MA = Mechanical Advantage
VR = velocity ratio = 
Distance moved by effort = 4.5m
distance moved by load = 1.5m
VR = 4.5/1.5 =3
Assuming efficiency is 100% (since friction can be ignored)
100% = MA/3 * 100%
1 = MA/3
MA = 3*1
MA = 3
Mechanical Advantage of the ramp is 3
Answer:
2.4583 ± 0.0207 seconds
Explanation:
The time period of a pendulum is approximately given by the formula ...
T = 2π√(L/g)
The maximum period will be achieved when length is longest and gravity is smallest:
Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds
The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:
Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds
If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.
T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2
T ≈ 2.4583 ± 0.0207 . . . seconds
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We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.
