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andrezito [222]
3 years ago
12

A rod is pivoted about its center and oriented horizontally. A 5.0-N force directed upward is applied 4.0 m to the left of the p

ivot and another upward 5.0-N force is applied 1.5 m to the right of the pivot. What is magnitude of the total torque about the pivot?
Physics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

The total torque is 27.5 Nm

Explanation:

Given;

5.0-N force directed upward is applied 4.0 m to the left of the pivot,

5.0-N force directed upward is applied 1.5 m to the right of the pivot,

Taking the moment about the pivot, the total torque is given by;

τ = Fr

where;

F is the appllied force

r is the radius of the force arm

τ = (5 N x 4 m) + (5 N x 1.5 m)

τ = 27.5 Nm

Therefore, the total torque is 27.5 Nm

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Two pans of a balance are 46.3 cm apart. The fulcrum of the balance has been shifted 0.633 away from the center by a dishonest s
soldier1979 [14.2K]

distance of each pan from the center or fulcrum is given as

r = 23.15 cm

now if dishonest shopkeeper shifted it by 0.633 cm from center

so distance on each side is given as

d_1 = 23.15 - 0.633 = 22.52 cm

d_2 = 23.15 + 0.633 = 23.78 cm

now the weight is balance as

W_1d_1 = W_2d_2

W(22.52) = W_2(23.78)

now we will have

W_2 = 0.95W

now we can find the percentage change as

percentage = \frac{W - W_2}{W} \times 100

percentage = 5%

5 0
4 years ago
A vicious dog is pulling his owner with 150N of force . If the owner is dragged 40 meters , how much work did the dog do ?
Angelina_Jolie [31]

Afor:6000Nm

Explanation: work=force×distance

Work=150×40

Work=6000Nm

4 0
3 years ago
Neutral hydrogen can be modeled as a positive point charge +1.6×10^−19C surrounded by a distribution of negative charge with vol
Archy [21]

Answer:

a) 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b) 3.466 × 10¹¹ N/C

Explanation:

a)

p(r) = -A exp ( - 2r/a₀)

Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV  =  -A  ₀∫^∞ ₀∫^π ₀∫^2π   exp ( - 2r/a₀)r² sinθdrdθd∅

Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e

now using integration by parts;

A = e / πa₀³

p(r) =  - (e / πa₀³) exp (-2r/a₀)

Now Net charge inside a sphere of radius a₀ i.e Qnet is;

= e - (e / πa₀³)  ₀∫^a₀ ₀∫^π ₀∫^2π  r² exp (-2r/a₀)dr

= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b)

Using Gauss's law,

E × 4πa₀ ² = Qnet / ∈₀

E = 4πa₀ ² × Qnet × 1/a₀²

E = 3.466 × 10¹¹ N/C

4 0
3 years ago
Suppose you want to test the hypothesis that plants grow taller when they receive more sunlight. Identify and independent variab
ollegr [7]
The result that should be established is in the form
y = f(x) 
where x, the amount of sunlight is the controlled (independent) variable,
y =  height (growth) that corresponds to the amount of sunlight. Therefore y depends on x.

Clearly,
x, the amount of sunlight is the independent variable. It can be controlled.
y, the measured amount of growth is the dependent variable.

Answer:
The independent variable is the amount of sunlight.
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5 0
4 years ago
1. What are valence electrons used for by an element?
jarptica [38.1K]

Answer:

An element's valence electron tells us about its ability to react and not react. More rules to this, but that's the gist of it. it also helps us form bonds

Explanation:

4 0
3 years ago
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