Answer:

Explanation:
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In this case, since the equation for the calculation of dilutions is:

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

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<u>Answer:</u> The final temperature of the system is 14.60°C
<u>Explanation:</u>
When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

......(1)
where,
q = heat absorbed or released
= mass of aluminium = 25.00 g
= mass of water = 100 g
= final temperature = ?°C
= initial temperature of aluminium = 100°C
= initial temperature of water = 10°C
= specific heat of aluminium = 0.900 J/g°C
= specific heat of water= 4.18 J/g°C
Putting values in equation 1, we get:
![25\times 0.900\times (T_{final}-100)=-[100\times 4.18\times (T_{final}-10)]](https://tex.z-dn.net/?f=25%5Ctimes%200.900%5Ctimes%20%28T_%7Bfinal%7D-100%29%3D-%5B100%5Ctimes%204.18%5Ctimes%20%28T_%7Bfinal%7D-10%29%5D)

Hence, the final temperature of the system is 14.60°C
Answer:
8 moles of C
Explanation:
From the question given above, the following equation was obtained:
3A + 2B —> 6C
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C
Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B
Answer:
Empirical Formula = C₁H₄ or CH₄
Explanation:
Data Given:
Mass of C = 12.0 g
Mass of H = 4 g
Step 1: <u>Calculate Moles of each Element;</u>
Moles of C = Mass of C ÷ At.Mass of C
Moles of C = 12.0 ÷ 12.0
Moles of C = 1.0 mol
Moles of H = Mass of H ÷ At.Mass of H
Moles of H = 4.0 ÷ 1.0
Moles of H = 4.0 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 53.924 ÷ 16.0
Moles of O = 3.370 mol
Step 2: <u>Find out mole ratio and simplify it;</u>
C H
1.0 4.0
1.0/1.0 4.0/1.0
1 4
Hence,
Empirical Formula = C₁H₄ or CH₄