Question

A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the new volume of the solution?

Answer 1

Answer:

$V_2=146mL$

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

$M_1V_1=M_2V_2$

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

$V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL$

Best regards!