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USPshnik [31]
3 years ago
13

Sulfur reacts with fluorine to produce three different compounds. The mass ratio of fluorine to sulfur for each compound is give

n in the following table:
Compound mass F : mass S
S2F10 2.962
SF4 2.370
SF6 3.555
Show that these data are consistent with the law of multiple proportions.
Chemistry
1 answer:
NARA [144]3 years ago
8 0

Answer:

Explanation:

Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32

Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32

Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .

Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :

94.78 g , 75.84 g , and 113.76 g

Their ratio = 94.78 : 75.84 : 113.76

divide them by 19

their ratio = 5 : 4 : 6

So these data are consistent with law of multiple proportion.

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Consider separate 1.0-L samples of He(g) and UF6(g), both at 1.00 atm and containing the same number of moles. What ratio of tem
diamong [38]
V =  \sqrt{x} 3 * R * T / MW

V = RMS velocity

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3 0
3 years ago
How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

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8 0
3 years ago
c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ
Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

\text{moles of propane}=\frac{44g}{44g/mol}=1mole

For the reaction of combustion reaction of propane, the equation follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

4mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 72 grams

Hence,  72 grams of water will be produced.

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8 0
3 years ago
Why do you think steeples and roofs might appear green, but a copper square does not?
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Because the copper roofs, have been outside for a while and oxidization has occurred.
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2 years ago
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