To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
The two consecutive integers the square root of 117 lies between are 10 and 11.
10 squared is 100 and 11 squared is 121.
Answer:
the answer is no.
Step-by-step explanation:
the x-value 2 keeps repeating which makes this not a function.
Answer:
x=101/65, y=-16/65. (101/65, -16/65).
Step-by-step explanation:
4x+9y=4
9x+4y=13
----------------
9(4x+9y)=9(4)
-4(9x+4y)=-4(13)
------------------------
36x+81y=36
-36x-16y=-52
----------------------
65y=-16
y=-16/65
4x+9(-16/65)=4
4x-144/65=4
4x=4+144/65
4x=404/65
x=(404/65)/4=101/65
x=101/65, y=-16/65.
1st
0.3/100*15000
=45
2nd
40/200*100
=20
=
