Question

A metal sphere of radius 10 cm carries a charge of 2.0 MicroCoulomb.What is the magnitude of the electric field 5.0 cm from the sphere's surface?

Answer 1

Answer:

E = 7200 J = 7.2 KJ

Explanation:

The electric field due to a sphere is similar to the electric field due to a point charge. It is calculated by the use of the following formula:

$E = \frac{kq}{r^2}$

where,

E = Electric Field = ?

k = Coulomb Constant = 9 x 10⁹ Nm²/C²

q = charge on sphere = 2 μC = 2 x 10⁻⁶ C

r = distance from the center of the sphere to the location = 5 cm = 0.05 m

Therefore,

$E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-6}\ C)}{(0.05\ m)^2}$

E = 7200 J = 7.2 KJ