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3 years ago

How can magnetic levitation be improved?

1 answer:

6 0

Https://www.researchgate.net/publication/335238337_A_New_Strategy_for_Improving_the_Tracking_Performance_of_Magnetic_Levitation_System_in_Maglev_Train/fulltext/5d5a958d299bf1b97cf546ba/A-New-Strategy-for-Improving-the-Tracking-Performance-of-Magnetic-Levitation-System-in-Maglev-Train.pdf?origin=publication_detail

The higher the phase margin the more stable is the system and for these tuned parameters, the phase margin is around
. Some researcher given their theory on the phase margin that there are changes of getting sluggish response for larger phase margin but using TLBO algorithm the settling time and as well as peak overshoot of the system shows better response as compared to conventional techniques.

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An insulating sphere is 8.00 cm in diameter and carries a 6.50 ÂµC charge uniformly distributed throughout its interior volume.

Kobotan [32]

Explanation:

(a) Formula to calculate the density is as follows.

$\rho = \frac{Q}{\frac{4}{3}\pi a^{3}}$

= $\frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.04)^{3}}$

= $2.42 \times 10^{-2} C/m^{3}$

Now, calculate the charge as follows.

$q_{in} = \rho(\frac{4}{3} \pi r^{3})$

= $2.42 \times 10^{-2} C/m^{3} \times 4.1762 \times (0.01)^{3}$

= $10.106 \times 10^{-8}$ C

or, = 101.06 nC

(b) For r = 6.50 cm, the value of charge will be calculated as follows.

$q_{in} = \frac{Q}{\frac{4}{3}\pi a^{3}}$

= $\frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.065)^{3}}$

= 7.454 $\mu C$

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ladessa [460]

Answer:

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