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SpyIntel [72]
2 years ago
15

(Score for Question 3:

Mathematics
2 answers:
Lynna [10]2 years ago
7 0

Answer:

-4.5n + 3

Step-by-step explanation:

-3(1.5n - 1)

= -3 x 1.5n + -3 x -1

= -4.5n + 3

jok3333 [9.3K]2 years ago
6 0
The answer for this question is -4
You might be interested in
Which values of x and y are solutions to the open sentence?       4y ≥ 3x + 2   A. x = 3, y = 0   B. x = 4, y = 3   C. x = 6, y
kobusy [5.1K]
Your answer would be C. x = 6, y = 5
This is because if you plug the numbers in to the inequality, we get:
(4 × 5) ≥ (3 × 6) + 2
20 ≥ 18 + 2
20 ≥ 20
which is correct.

I hope this helps!
5 0
3 years ago
Read 2 more answers
Please help me with this explain!!!!!
erik [133]
Given:
Cylinder: radius = 8 yd; height = 4 yd
Surface Area = 2 π r h + 2 π r²
SA = 2 * 3.14 * 8 yd * 4yd + 2 * 3.14 * (8yd)²
SA = 200.96 yd² + 401.92 yd²
SA = 602.88 yd²
Volume = π r² h
V = 3.14 * (8yd)² * 4yd
V = 803.84 yd³

Dimension is cut in half. radius = 4yds ; height = 2yds
S.A = 2 * 3.14 * 4yd * 2yd + 2 * 3.14 * (4yd)²
S.A = 50.24 yd² + 100.48 yd²
SA = 150.72 yd²
V = 3.14 * (4yd)² * 2yd
V = 100.48 yd³

SA =
602.88 yd² - 150.72yd² = 452.16 yd²
V =
803.84 yd³ - 100.48 yd³ = 703.36 yd³
7 0
2 years ago
Alicia wants to bake a cake with ⁹/10 grams of flour.However,she only has ⅓ grams of flour she needs.How much does she have?
natali 33 [55]

Answer:

We know that:

She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)

She only has 1/3 of the amount she needs.

How much flour does she have?

Well, she needs 9/10 grams, and she has one-third of that.

Then she has (1/3) times (9/10) grams, this is:

F = (1/3)*(9/10) grams

F = (1*9)/(3*10) grams

F = 9/30 grams

That is the amount of flour that she has.

6 0
2 years ago
Which one would it be and why.
SVETLANKA909090 [29]

Answer:B because its the rule in algebra that you must gave 1 as a zero

Step-by-step explanation:

5 0
3 years ago
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
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