Answer:
Femur
Explanation:
The femur is the single bone of the thigh region. It articulates superiorly with the hip bone at the hip joint, and inferiorly with the tibia at the knee joint.
Answer:
The speed of the chair just before impact is 22.54 m/s
Explanation:
From the question,
The chair was initially at rest, that is, the initial velocity of the chair is 0 m/s.
Since the chair was thrown from a balcony, the chair will fall freely due to gravity.
To determine the speed of the chair just before impact, we will determine the final velocity of the chair.
From one of the equations of linear motion for objects falling freely due to gravity,
v = u + gt
Where v is the final velocity
u is the initial velocity
g is the acceleration due to gravity (Take g = 9.8 m/s²)
and t is time
From the question,
u = 0 m/s
t = 2.3 secs
Then, v = u + gt becomes
v = 0 + (9.8)(2.3)
v = 9.8 × 2.3
v = 22.54 m/s
Hence, the speed of the chair just before impact is 22.54 m/s.
Answer:
A body moving on a circular path with constant speed that is undergoing a uniform circular motion has variable velocity. The direction of velocity changes each moment and hence the velocity is not constant.
Explanation:
hope it help u himal
Thank u
Answer:
protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
Explanation:
mass number: the sum of the number of protons and
neutrons in an atom
this is key as it explains that protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
Answer:
2.15 m/s²
Explanation:
We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:
Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C
Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C
Electrical constant (K) = 9×10⁹ Nm²/C²
Distance apart (r) = 0.925 m
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 11.5×10¯⁶ × 7.55×10¯⁶/ 0.925²
F = 0.781425 / 0.855625
F = 0.91 N
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass of object (m) = 0.423 Kg
Force (F) = 0.91 N
Acceleration (a) =?
F = ma
0.91 = 0.423 × a
Divide both side by 0.423
a = 0.91 / 0.423
a = 2.15 m/s²
Thus, the magnitude of the object's acceleration is 2.15 m/s²